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jok3333 [9.3K]
3 years ago
15

Find the values if a and b such that x squared + 2x -7 = (x+a) squared + b​

Mathematics
1 answer:
stealth61 [152]3 years ago
6 0

Given:

x^2+2x-7=(x+a)^2+b

To find:

The values of a and b.

Solution:

We have,

x^2+2x-7=(x+a)^2+b

It can be written as

(x^2+2x)-7=(x+a)^2+b

Add and subtract square of half of coefficient of x in the parenthesis.

(x^2+2x+(\dfrac{2}{2})^2-(\dfrac{2}{2})^2)-7=(x+a)^2+b

(x^2+2x+1^2)-1-7=(x+a)^2+b

(x+1)^2-8=(x+a)^2+b     [\because (x+y)^2=x^2+2xy+y^2]

(x+1)^2+(-8)=(x+a)^2+b

On comparing both sides, we get

a=1

b=-8

Therefore, the value of a is 1 and the value of b is -8.

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