One hypothesis that explains the result is : A) Two genes are involved with 12:3:1 epistasis, such that A_B_ and A_bb are black, aaB_ is brown,and aabb is green.
Explanation:
- This is a case of Dominant Epistasis.
- When two genes are involved and presence of dominant allele of one gene masks the effect of either allele of the second gene then the epistasis is termed as dominant epistasis.
- In the given case black :brown: green ratio is approximately equal to 12:3:1.
- Here presence of a dominant A allele that is responsible for the black colour masks the effect of either allele of B. Therefore A_B_ and A_bb produces black beetles
- Again , absence of dominant A allows B to express itself and Brown beetles are produced thus aaB_ is brown.
- When both the genes are present as recessive alleles, neither brown nor black colour is expressed and the beetles are green.Thus, aabb are green.
The answer is D. Species A will have fewer phenotypes.
Alleles are alternative forms of a gene. In species A, the leaf color is controlled by two alleles, for example, P and Q. They will have three possible genotypes - PP, PQ, and QQ. Three different genotypes give maximum three phenotypes.In species B, leaf color is controlled by three alleles, for example, L, M, and N. They will have six different genotypes - LL, LM, LN, MM, MN, and NN. Six different genotypes give maximum 6 phenotypes.
Answer:
•The hydrolysis of ATP to drive a thermodynamically unfavorable reaction.this process is ATP coupling
Explanation:
For example, the conversation of glucose to glucose -6-phosphate.
I think it would condense into liquid droplets
Explanation:
what are the answer options