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3 years ago

What’s 3/6 + 10/12?

Mathematics

2 answers:

jarptica [38.1K]3 years ago

6 0

3/6 + 10/12 = 4/3. Therefore your answer is 4/3

Snezhnost [94]3 years ago

4 0

3/6=6/12

6/12+10/12=16/12 or 1 1/3

The answer is 1 and 1/3

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A plane cuts through a cone perpendicular to the base of the cone. What shape is formed by this intersection

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A Ferris wheel can accommodate 65 people in 15 minutes. How many people could ride the Ferris wheel in 2 hours? What was that ra

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Answer:

520 people in 2 hours

rate = 260 people per hour

Step-by-step explanation:

change minutes to hours

15 minute* 1 hr/60 minutes = .25 hrs

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using cross products

65 * 2 = .25 * x

130 = .25x

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520 =x

520 people

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--------------- = ------------------

.25 hrs 1 hrs

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4 years ago

What is the type of sweet wine made in tuscany using dried grapes and extensive aging?

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3 0

3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

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4 0

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