Answer:
If you want me to find out how you got it, please dm me.
To change it into slope intercept (y=mx+b) you just replace the inequality with an equality and isolate y
x<=2:
x=2=y-> y=2 or y=2+0x
2x-3y>=4:
2x-3y=4
2x-4=3y
(2/3)x-(4/3))=y
y=(2/3)x-(4/3)
x+y>0:
x+y=0
y=-x or y=-x+0
2/3 thtas the number you are looking for
Start with #47. To find the critical values, you must differentiate this function. x times (4-x)^3 is a product, so use the product rule. The derivative comes out to f '(x) = x*3*(4-x)^2*(-1) + (4-x)^3*1 = (4-x)^2 [-3x + 4-x]
Factoring this, f '(x) = (4-x)^2 [-3x+4-x]
Set this derivative equal to zero (0) and solve for the "critical values," which are the roots of f '(x) = (4-x)^2 [-3x+4-x]. (4-x)^2=0 produces the "cv" x=4.
[-3x+ (4-x)] = 0 produces the "cv" x=1. Thus, the "cv" are {4,1}.
Evaluate the given function at x: {4,1}. For example, if x=1, f(1)=(1)(4-1)^3, or 2^3, or 8. Thus, one of the extreme values is (1,8).
Answer:
169.70563
Step-by-step explanation:
If it's pythagorean theoram then i used 
a and b would be 120.
doing all that would get you the answer.
if this helped...great.
