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stiv31 [10]
2 years ago
10

(I'LL GIVE BRAINLIEST AND EXTRA POINTS IF YOU HELP!!!)

Mathematics
2 answers:
Nonamiya [84]2 years ago
6 0

Answer:

24/6048 = 252

Step-by-step explanation:

brainlest plz

and why does she have so many beads

Dmitriy789 [7]2 years ago
3 0

Answer:

she said 24 only goes into 60 once, when in reality it can go in twice

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The main numbers and ratios or rates depending on the problem
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a block has two red sides, two green sides, one blue side and one yellow side what is the probability that when the block is rol
olga55 [171]

Answer:

2/6

Step-by-step explanation:

There are 6 sides, and two are green. That makes it 2/6

8 0
3 years ago
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40 is the sum of 15 and Craig's savings.<br> Use the variable c to represent Craig's savings.
andrew-mc [135]
40=15+c

Hope it helps
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2 years ago
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On Monday, the ABC Company stock was at $12.80 per share. On Tuesday it gained $3.42, and then lost $9.70 on Wednesday. What is
solong [7]

Answer:

Step-by-step explanation:

12.80+3.42= 16.22

16.22-9.70= 6.52 that's your answer

6 0
3 years ago
In a study of the effect of college student employment on academic performance, the following summary statistics for GPA were re
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μemployed(μ1) be the sample mean of students who are employed and μnot employed(μ2) be the sample mean of students who are not employed

The random variable is μ1 - μ2 = difference in the mean of the employed and unemployed students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(μ1 - μ2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 3.22

μ2 = 3.33

s1 = 0.475

s2 = 0.524

n1 = 172

n2 = 116

t = (3.22 - 3.33)/√(0.475²/172 + 0.524²/116)

t = - 1.81

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.475²/172 + 0.524²/116]²/[(1/172 - 1)(0.475²/172)² + (1/116 - 1)(0.524²/116)²] = 0.00001353363/0.00000005878

df = 230

We would determine the probability value from the t test calculator. It becomes

p value = 0.036

Since alpha, 0.05 > than the p value, 0.036, then we would reject the null hypothesis.

Therefore, at a 5% significant level, this information support the hypothesis that for students at this university, those who are not employed have a higher mean GPA than those who are employed

3 0
3 years ago
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