Answer:
The greatest common factor of 12m^2 and 9b^4 is 3.
I hope this could help, let me know if you need anymore help.
The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).


Therefore, 

t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :

= 0.020908803
The p value is 0.0209

So we reject the null hypothesis and conclude that 
Answer:
1 :)
Step-by-step explanation:
10 meters by 3 meters
P= 10+10+3+3=26
A= 10×3=30
hope this helps :)