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Doss [256]
3 years ago
13

(p v q') ^ (p' v q')

Mathematics
1 answer:
Otrada [13]3 years ago
3 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

( p v q' ) ^ ( p' v q' ) = ( p ^ p' ) v q' =

False v q' = q'

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Sorry i couldn't write better.

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Solve for W.<br><br> 7=LW<br><br> W=
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Answer:

this is the chan of formula from 7=LW to

w =7/L

because we divided both sides by L.

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Point A is located at (5, 10) and point B is located at (20, 25).
Alla [95]
Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at  a ratio of 7, thus 3:7,

\bf \left. \qquad  \right.\textit{internal division of a line segment}&#10;\\\\\\&#10;A(5,10)\qquad B(20,25)\qquad&#10;\qquad 3:7&#10;\\\\\\&#10;\cfrac{AC}{CB} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(5,10)=3(20,25)\\\\&#10;-------------------------------\\\\&#10;{ C=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\&#10;-------------------------------

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Number 2 how do I do it I really do not know how to do it
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Um Mabry ask for help or reread
8 0
3 years ago
Read 2 more answers
The angle between the complex numbers 2+2i and -7
anygoal [31]

Answer:Consider the right triangle formed by the complex number in the Argand-Gauss plane and it's projections on the axis. – José Siqueira Nov 12 '13 at 17:21

In particular what is the definition of sine of theta in terms of the known sides of the above mentioned right triangle? – Adam Nov 12 '13 at 17:27

Add a comment

3 Answers

1

Consider the following Argand-diagram

enter image description here

The y-axis is the imaginary axis and the x-axis is the real one. The complex number in question is

x+yi

To figure out θ, consider the right-triangle formed by the two-coordinates on the plane (illustrated in red). Let θ be the angle formed with the real axis.

tanθ=yx

⟹tan−1(yx)

The hypotenuse of the triangle will be

x2+y2−−−−−−√

Therefore,

Step-by-step explanation:

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3 years ago
I'd really appreciate it if someone could help me with these square problems :/
adelina 88 [10]
I would but I don’t want to ;/
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3 years ago
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