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Inga [223]
4 years ago
10

2-(3-a)=-4 please help me i did not understand the question

Mathematics
1 answer:
Leokris [45]4 years ago
5 0

Answer:

A= -3

Step-by-step explanation:

The parenthesis means multiplication with the number before it, it is a negative blank meaning you just switch the signs. 3-a becomes a-3. then you add 2 into it, making the equation A-1=-4. If you add 1 to both sides you get A=-3 To check the answer plug A back in. 2-(3-(-3))=-4    The negatives cancel each other out, making the equation 2-(6)=-4 or 2-6=-4 which is correct.

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A = (a,7) and m = (2a,2) and m is the midpoint of ab what are the coordinates of B?
saul85 [17]

Answer:

Step-by-step explanation:

Consider the coordinates of B(x,y).

as M is midpoint of AB so,

2a = (x+a)/2

4a = x + a

x = 4a - a

x = 3a

Now for we will find y

2 = (7+y)/2

4 = 7 + y

y = 4 - 7

y = -3

Hence coordinates of B are ( 2a, -3 )

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3 years ago
Dustin is stuck at the top of a ferris wheel. his mother is standing 38 feet from the base of the wheel watching him. if the ang
N76 [4]
To get the height to the nick we use the trigonometry formula:
tan θ=opposite/adjacent
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thus
h=38 tan 73
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4 0
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A Square has the vertices at (-2,6) (6,1) (1,-7) (-7,-2). At what point do the diagonals of the square intercect
DerKrebs [107]

Answer: At point (-\frac{1}{2},-\frac{1}{2})

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In other words, the diagonals of a square meet at their midpoint, which is found as the following:

(x,y) = (\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2})

The opposite vertices of the given square are (-2,6) and (1,-7).

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(x,y) = (-\frac{1}{2},-\frac{1}{2} )

The diagonals of square with vertices (-2,6)(6,1)(1,-7)(-7,-2) intersect at point (-\frac{1}{2},-\frac{1}{2} ).

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