First statement: False. Points K, M and N form a triangle.
Second statement: True. Points J, K, and Q are on the same line.
Third statement: False. KN and MQ intersect at N, not at R.
Fourth statement: False. JQ and KM intersect at K, but MQ does not pass through it.
Fifth statement: True. By definition, there is always only 1 line that can be drawn between 2 given points.
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Step-by-step explanation:
log (√1000000x)
Rewrite √1000000x as (1000000x)1/2.
expand long ((1000000x)1/2) by moving 1/2
oby moving logarithm.
1/2 longth (1000000x)
Rewrite
log
(1000000x) as log(1000000)+log(x).
1/2(log(1000000)+log(x))
Logarithm base 10 of 1000000 is 6.
1/2(6+log(x))
Apply the distributive property.
1/2.6+1/2 log(x)
Cancel the common factor of 2.
3+1/2 long(x)
Combine 1/2 and log(x)
3+ long(x)/2
400, if you can buy 4 tickets for $6 you can buy 400 for $600
The second one:
3^7 x 3^(86/10) x 3^(9/1000)
That is because when you multiply powers with the same base ( in this case they are all 3), you just leave the base as it is and add the exponents
so it is basically 3^(7 + 86/100 + 9/1000) which is 3^7.869
