Exponentiate the log or In because Exponentials are inverses of Logs and lns.
Answer:
Since the calculated value of z= 2.82 does not lie in the critical region the null hypothesis is accepted and it is concluded that the sample data support the authors' conclusion that the proportion of the country's boys who listen to music at high volume is greater than this proportion for the country's girls.
The value of p is 0 .00233. The result is significant at p < 0.10.
Step-by-step explanation:
1) Let the null and alternate hypothesis be
H0: μboys − μgirls > 0
against the claim
Ha: μboys − μgirls ≤ 0
2) The significance level is set at 0.01
3) The critical region is z ≤ ± 1.28
4) The test statistic
Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]
Here p1= 397/768= 0.5169 and p2= 331/745=0.4429
pc = 397+331/768+745
pc= 0.4811
qc= 1-pc= 1-0.4811=0.5188
5) Calculations
Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]
z= 0.5169-0.4429/√ 0.4811*0.5188( 1/768+ 1/745)
z= 2.82
6) Conclusion
Since the calculated value of z= 2.82 does not lie in the critical region the null hypothesis is accepted and it is concluded that the sample data support the authors' conclusion that the proportion of the country's boys who listen to music at high volume is greater than this proportion for the country's girls.
7)
The value of p is 0 .00233. The result is significant at p < 0.10.
Answer:
7/24 Is The Answer!
Step-by-step explanation:
Division of fractions is equivalent to multiplication by the reciprocal of the second fraction:
1/4 Divided by 6/7 = 1/4 ₓ 7/6
Once rearranged, multiply all of the numerators by each other. Do the same with the denominators and form a new fraction with these values:
1/4 times 7/6 = 7/24
The result Is
1/4 divided by 6/7 = 7/24
Answer:
amplitude = 2
Step-by-step explanation:
the amplitude is the distance from the x- axis(midline ) to the maximum value , that is
amplitude = 2
Answer:
1lb= 16oz
24(16)= 384
24lb= 384oz
Step-by-step explanation:
24lb is greater than 124oz after you convert the pounds to oz
if i'm correct please mark me as brainliest
