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jek_recluse [69]
3 years ago
11

6.An organization wants to implement a remote dial-in server to ensure that personnel can connect to the organization's network

from remote locations. The authentication protocol must include encryption to prevent hackers from accessing the network. Which protocol should be used
Computers and Technology
1 answer:
Sauron [17]3 years ago
5 0

Answer:

Challenge-Handshake Authentication Protocol (CHAP).

Explanation:

In Computer technology, authentication can be defined as the process of verifying the identity of an individual or electronic device. Authentication work based on the principle (framework) of matching an incoming request from a user or electronic device to a set of uniquely defined credentials.

Basically, authentication ensures a user is truly who he or she claims to be, as well as confirm that an electronic device is valid through the process of verification.

In this scenario, an organization wants to implement a remote dial-in server to ensure that personnel can connect to the organization's network from remote locations. The authentication protocol must include encryption to prevent hackers from accessing the network.

Hence, the protocol which should be used is Challenge-Handshake Authentication Protocol (CHAP).

A Challenge-Handshake Authentication Protocol (CHAP) can be defined as a standard network access control protocol in which a client program dials in to a network access server to receive a random value and identification number that can only be used once.

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A variable of type unsigned short stores a value of 0. If the variable value is incremented, what exception will occur?A. No exc
yulyashka [42]

There are different kinds of variable. The answers are below;

  • If the variable value is incremented, therefore, No <u>exception </u>will occur.
  •  If the variable value is incremented, An <u>Overflow </u>will occur
  • If the variable value is decremented no exception will occur.

<h3>What is Underflow?</h3>

Underflow is a known to be a process or exception that happens if a number calculation is too small to be shown by the CPU or memory.

what causes a overflow is the Adding to a variable when its value is at the upper end of the datatype range.

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brainly.com/question/24751617

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3 years ago
Write a Python program that calculates the product of all odd numbers between 1 and 1111, using the for loop and the range funct
Verdich [7]

Answer:

answer = 1

for i in range(1, 1111, 2):

   answer *= i

print(answer)

Explanation:

The result is: 1867661487583158519937007997593731768674710592395936453814589179168970488627486922435352153202170177468180449036460330489883227953920786805094193880129176242750706494757506292242513096874889912138041641434433821228611320718319399459865627764413363015842622109227229695987391658459583021203370153652674793604946843921588657975214048903891877905278158326695472816452229608456097609116519045810867129060580585147954461081838126748579250596173066031868654116793938302170110362754673884690241925481893823673916009076351110558645412222773118927086453253674705050538434792606852567079575854841390964177213252754015145265445261542957834970632574543428225247242488955307645556148572185949820791464992259236192606284766174288372574869081003838416637821295590820946372288692264397746175279884156247638880688731656093911498376399334121390341627286952705811600644061948275361728751637451512725082376969150560038940786375629981515779279396085386198351152320090978588430101676704229895114350886499131456005886390334346220238579530541662198038029084029447261270224035584412162390327122500762501298502491940263477106501424307313102108306951120296510397274150253596249878157904612419169854362011297315737418348969961989528582716326033338095891309343771263480361729925724962879195879868448756011080612327885089033870698092857432512937836751109257833022671357201287794589267907954829015862301288301132960212133783812669550047024479011437136932727298699319362640380859375

7 0
3 years ago
What Windows utility can enable you to shut down an unresponsive application?
boyakko [2]

Answer:

Task manager

Explanation:

Allows you to force quit applications.

4 0
3 years ago
Read 2 more answers
Write a method called findNames that meets the following specs: It takes two arguments: a list of strings, allNames, and a strin
Anna11 [10]

Answer:

public class Solution {

   public static void main(String args[]) {

       String[] allNames = new String[]{"Bob Smith", "Elroy Jetson", "Christina Johnson", "Rachael Baker", "cHRis", "Chris Conly"};

       String searchString = "cHRis";

       

       findNames(allNames, searchString);

   }

   

   public static void findNames(String[] listOfName, String nameToFind){

       ArrayList<String> resultName = new ArrayList<String>();

       

       for(String name : listOfName){

           if (name.toLowerCase().contains(nameToFind.toLowerCase())){

               resultName.add(name);

           }

       }

       

       for(String result : resultName){

           System.out.println(result);

       }

   }

}

Explanation:

The class was created called Solution. The second line define the main function. Inside the main function; we initialized and assign an array called allNames to hold the list of all name. Then a String called searchString was also defined. The searchString is the string to search for in each element of allNames array. The two variables (allNames and searchString) are passed as argument to the findNames method when it is called.

The method findNames is defined and it accept two parameters, an array containing list of names and the name to search for.

Inside the findNames method, we initialized and assigned an ArrayList called resultName. The resultName variable is to hold list of element found that contain the searchString.

The first for-loop goes through the elements in the allNames array and compare it with the searchString. If any element is found containing the searchString; it is added to the resultName variable.

The second for-loop goes through the elements of the resultName array and output it. The output is empty if no element was found added to the resultName variable.

During comparison, the both string were converted to lower case before the comparison because same lowercase character does not equal same uppercase character. For instance 'A' is not same as 'a'.

8 0
3 years ago
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