Answer:
20
Explanation:
assuming the print statement is not indented, the program effectively calculates 2+5+6+7.
The range(...) is <em>excluding </em>the end value (8 in this case).
Answer:
The method definition to this question can be given as:
Method definition:
double max(double x, double y) //define method with double parameter
{
if (x>=y) //check condition.
return x; //return value
else
return y; //return value
}
double max(int x, int y) //define method with integer parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
double max(char x, char y) //define method with char parameter
{
if (x>=y) //check condition
return x; //return value
else
return y; //return value
}
Explanation:
The above method definition can be described as below:
- In the first method definition first, we define a method that is "max()". In this method we pass two variables as a parameter that is "x and y" and the datatype of this is double. Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the second method definition, we define a method that is same as the first method name but in this method, we pass two integer variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
- In the third method definition, we define a method that is same as the first and second method name but in this method, we pass two char variable that is "x and y". Then we use a conditional statement. In the if block we check if variable x is greater then equal to y then it will return x else it will return y.
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