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2 answers:
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Answer:
x=1, y=-5
Step-by-step explanation:
Given equations are:
In order to solve the equation
Multiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting them
So,
Eqn 1 becomes
15x+50y=-235
Eqn 2 becomes
15x-21y=120
Subtracting 2 from a
15x+50y - (15x-21y) = -235-120
15x+50y-15x + 21y = -355
71y = -355
y = -355/71
y =-5
Putting y= -5 in eqn 1
3x+10(-5) = -47
3x -50 = -47
3x = -47+50
3x = 3
x = 3/3
x = 1
Hence the solution is:
x=1, y=-5
The set is linearly dependent.
To explicitly prove this, we need to show there is at least one choice of constants such that
or equivalently,
which is the same as solving the system of equations
From the first and last equations, we have and
. Substituting these into the second equation leaves us with
, and so the overall solution set is
for which there are infinitely many not-all-zero solutions.