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brilliants [131]
3 years ago
7

Solve for y. 2(3y-7)=16​

Mathematics
2 answers:
miv72 [106K]3 years ago
5 0

Answer:

y = 5

Step-by-step explanation:

2(3y - 7) = 16

distributive property:

2(3y - 7) = 16

6y - 14 = 16

add 14 on both sides

6y - 14 + 14 = 16 + 14

6y = 30

divide both sides by 6 :

\frac{6y}{6} = \frac{30}{6}

y = 5

to check, subtitute 5 for y

2 (3(5) - 7) = 16

2(18 - 7) = 16

30 - 14 = 16

16 = 16

Nimfa-mama [501]3 years ago
4 0

Answer:

y=5

Step-by-step explanation:

First, distribute the 2 to the 3y and -7

6y - 14 = 16

Second, add 14 to both sides.

6y = 30

Third, divide both sides by 6

y = 5

As you can see y equals 5!

I hope the explanation helped and have a great day!

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Answer: The expenses of the fundraiser is $1500

Step-by-step explanation:

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A negative profit means the expenses exceeded the income from tickets. Looking at the model, for the charity organization to make profits, the product of the number of tickets sold and the cost per ticket must exceed $1500. If it is below $1500, then it is a negative profit. This means that the expenses is $1500

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Write the slope-intercept from of the equation of the line described. Through (-2, -1) perpendicular to y = 1/4x
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Step-by-step explanation:

Slope Intercept Form is "y = mx + b"

What it means?

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"b" - y intercept (0,b)

So, we are given the slope, but not the y intercept..

For now, lets fill in the slope.

y = 1/4x +  b

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Fill it into the equation and solve for b.

-1 = 0.25(-2) + b

-1 = -0.50 + b

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^ I think that is correct, sorry if it's wrong.

5 0
3 years ago
1. What is the vertex form of the equation?
sergeinik [125]

1.vertex form is y=a(x-h)^2+k

to get into vertex form, complete the square

y=-x^2+12x-4

step 1: group x terms

y=(-x^2+12x)-4

step 2: factor coefient in front of x^2 term

y=-1(x^2-12x)-4

prep for next step: take 1/2 of linear (1st dgree term) and square it

\frac{-12}{2}=-6, (-6)^2=36

step 3: add positive and negative of that previous number inside the parenthasees

y=-1(x^2-12x+36-36)-4

factor perfect squaer trionmial

y=-1((x-6)^2-36)-4

take out that -36 by expansion

y=-1(x-6)^2+36-4

y=-1(x-6)^2+32



2. factor out the 2

2(x^2+8x+12)

what 2 numbers multiply to get 12 and add to get 8?

2 and 6

2(x+2)(x+6)


3.

for ax^2+bx+c=0

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

in our case

x^2-7x-6=0

a=1, b=-7, c=-6

x=\frac{-(-7) \pm \sqrt{(-7)^2-4(1)(-6)}}{2(1)}

x=\frac{7 \pm \sqrt{73}}{2}

so x=\frac{7+\sqrt{73}}{2} and x=\frac{7-\sqrt{73}}{2}



4. remember that i=\sqrt{-1} so i^2=-1

treat i as a variable

(-2i)(8i)=

(-2)(i)(8)(i)=

(-2)(8)(i)(i)=

(-16)(i^2)=

(-16)(-1)=

[tex}16[/tex]

8 0
3 years ago
Read 2 more answers
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