Answer:
The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0518
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
In this question:
. So


The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
500 people took the survey.
12 out of 15 people is 80% of the population. 12/15 = 0.80
Thus, 80% of the population prefers eating in the restaurant.
If 400 represents the people who prefers eating in the restaurant; then, 400 is the 80% of the population. To get the total population or 100%, we must divide 400 by 0.80 or 80%
400 / 0.80 = 500 people.
Out of the 500 people, 400 selected eating in the restaurant while the remaining 20% of the population or 100 people selected cooking at home.
Answer: I think its 2.09
Step-by-step explanation:
But i'm not sure.
Answer:
67th percentile
Step-by-step explanation:
If the mean is 8 with a standard deviation of 1.5, the percentile rank of a shoe with at least a size of 9 is 66.6 repeating, or 67th if rounded.