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Shkiper50 [21]
3 years ago
12

The diameter of a circle is 14 ft. Find its area to the nearest tenth.

Mathematics
2 answers:
AleksandrR [38]3 years ago
4 0

Answer:

Solution given:.

diameter=14ft

radius [r]=14/2=7ft

Now

Area of circle =πr²=π×7²=154ft²

DedPeter [7]3 years ago
3 0

Answer:

615.8

Step-by-step explanation:

A=πr2=π·142≈615.75216

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the axis of symmetry for the graph of the function is f(x) = 1/4x2 bx 10 is x = 6. what is the value of b?
Lady bird [3.3K]

we have

f(x)=\frac{1}{4} x^{2} +bx+10

This is a vertical parabola open upward

The axis of symmetry is equal to the x-coordinate of the vertex

The vertex is the point (h,k)

the equation of the axis of symmetry is x=h

In this problem

x=6

so the x-coordinate of the vertex is h=6

<u>Convert the quadratic equation in vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-10=\frac{1}{4} x^{2} +bx

Factor the leading coefficient

f(x)-10=\frac{1}{4}(x^{2} +4bx)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-10+b^{2}=\frac{1}{4}(x^{2} +4bx+4b^{2})

Rewrite as perfect squares

f(x)+(b^{2}-10)=\frac{1}{4}(x+2b)^{2}

f(x)=\frac{1}{4}(x+2b)^{2}-(b^{2}-10)

remember that

h=6

so

(x+2b)=(x-6)

2b=-6

b=-3

substitute in the equation

f(x)=\frac{1}{4}(x-6)^{2}-((-3)^{2}-10)

f(x)=\frac{1}{4}(x-6)^{2}+1

therefore

<u>the answer is</u>

b=-3


8 0
4 years ago
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I need help plss!! Thankyou in advance!!
ololo11 [35]

Answer:15

Step-by-step explanation:

3 0
3 years ago
Pls help it's due tonight!!!<br> :((((((
statuscvo [17]
I think AB is 3!!

i hope i’m right good luck ,:D
4 0
3 years ago
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