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3 years ago

The diameter of a circle is 14 ft. Find its area to the nearest tenth.

Mathematics

2 answers:

AleksandrR [38]3 years ago

4 0

Answer:

Solution given:.

diameter=14ft

radius [r]=14/2=7ft

Now

Area of circle =πr²=π×7²=154ft²

DedPeter [7]3 years ago

3 0

Answer:

615.8

Step-by-step explanation:

A=πr2=π·142≈615.75216

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Given: measure of angle KJ = 124°, measure of IC =38°<br><br> Find: m∠CQJ, m∠LIJ.

VLD [36.1K]

Answer:

Part 1) $m$

Part 2) $m$

Step-by-step explanation:

Part 1) Find the measure of angle CQJ

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite.

$m$

$arc\ IK+arc\ CJ=360\°-(arc\ IC+arc\ KJ)$

substitute the values

$arc\ IK+arc\ CJ=360\°-(38\°+124\°)=198\°$

$m$

Part 2) Find the measure of angle LIJ

step 1

Find the measure of angle IJL

we know that

The inscribed angle is half that of the arc it comprises.

$m$

substitute the values

$m$

step 2

Find the measure of angle ILJ

we know that

The measurement of the external angle is the semi-difference of the arcs it encompasses.

$m$

substitute the values

$m$

step 3

Find the measure of angle LIJ

Remember that the sum of the interior angles of a triangle must be equal to 180 degrees

In the triangle LIJ

$m$

substitute the values

$m$

3 0

4 years ago

Order each set of fractions as indicated: 1/9, 1/20, 1/25, 1/2, 1/50

Bond [772]

Use the least common denominator (LCD) to write these fractions as equivalent fractions with like denominators, and then compare them two at a time

3 0

3 years ago

Are two isosceles triangles always similar? Explain. (1 point)

lara [203]

Answer:

No, because the ratios of the sides that form the vertex angles are the same, but the vertex angles may not be congruent.

Step-by-step explanation:

I just took the quick check

8 0

3 years ago

A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of

lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean x = 31,5

Sample standard deviation s₂ = 8,35

Sample size n₂ = 11

Ti-84 Calculator

Sample mean y = 46,2

Sample standard deviation s₁ = 9,99

Sample size n₁ = 12

t(s) = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s) = 12,9 / √(99,8/12) + (69,72/11)

t(s) = 12,9 / √8,32 + 6,34

t(s) = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis H₀ y - x > 1,80

Altenative Hypothesis Hₐ y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c) critical value for

t(c) α; n₁ +n₂-2 df = 12 +11 -2 df = 21

If we choose CI = 95 % then α = 5 % α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0

3 years ago

A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution

xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0

3 years ago

Read 2 more answers