It is an open circle on 2 and then pointing to the left
Distance: (sqroot(x2-x1)^2 + (y2-y1)^2)
sqroot(1-3)^2 + (8-6)^2
sqroot(-2)^2 + (2)^2
sqroot(4) + 4
Square root of 8 = 2.82843
Round to nearest tenth
Solution: 2.8
Answer:
98
Step-by-step explanation:
So we have the two functions:

And we want to find the value of r(g(4)).
To do so, first find the value of g(4):

Multiply:

Subtract:

Now, substitute this into r(g(4)):

And substitute this value into r(x):

Square:

Subtract:

Therefore:

Answer:
Below.
Step-by-step explanation:
As both the right sides of the 2 equations are equal to y, by the transitive law of equality 3x + 1 = -2x + 3.
W then solve this equation for x then substitute this value of x in the first equation ( y = 3x + 1) to find the value of y.