Answer:
r equals StartFraction C Over 2 pi EndFraction
Step-by-step explanation:
we know that
The circumference of a circle is equal to
where
r is the radius of the circle
Solve for r
That means -----> isolate the variable r
Divide by 2π both sides
Simplify right side
Rewrite
so
r equals StartFraction C Over 2 pi EndFraction
Since this is an obtuse triangle, Point O is not equidistant from A, B, and C. Point O is not on the perpendicular bisectors, so the third statement is true. Point O is equidistant from AB, BC, and CA because these lines are pressed against the circpe in a mannered way.
Answer:
1st one: (x-2)(x+10)
2nd one: (x-7)(x-3)
Step-by-step explanation:
22/100:
You can actually divided the numerator and denominator by a number that can go into both 22 and 100 but also not get a remainder.
So 22/2= 11
And 100/2=50
Combined you get 11/50
Hope it helps!!!
