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Brums [2.3K]
3 years ago
14

-6>t-(-13) slove for the inequality

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

-19>t

Step-by-step explanation:

-6>t-(-13)

-6>t +(13)

Subtract 13 from each side

-6-13 > t+13-13

-19>t

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Help me with this, anyone.
slava [35]

Answer: y=13, A. f(x)=13

Step-by-step explanation:

4 0
2 years ago
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Which expression is equivalent to 4g + 2g + 10
const2013 [10]
The actual answer is 6g+10
8 0
3 years ago
The diagram below shows a stair which is 1 foot deep.<br><br>mark as brilliant! help​
kramer
Answer is C. 1 2/3

A^2 + B^2 = C^

A^2 + 1 = 1 2/3^2

A^ + 1 = 2 7/9

A^2 = 2 7/9

Square root of both makes it
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8 0
3 years ago
A rectangular room measures 15 feet by 20 feet. The ceiling is 9 feet high. What is the total area of the four walls? (to the ne
frozen [14]

Answer:

Answer:

825 feet of area of the wall  required to be  painted.

Explanation:

Given:

Length of the room = 15 feet

Width of the room =12 feet

Height of the room = 9-foot

Size of the door= 3 feet x 7 feet

To find:

The area of the walls that requirespainted=?

Solution:

We know that,  

Area of walls that need paint = total surface area of room – area of door that doesn’t need paint…………(1)

Finding the Total area of the room:

room is cuboidal shape,  

Then, its total surface area = 2(lb + bh + hl)

Where

h is height,  

l is length,

b is width  

Substituting the values,

Total surface area = 2(15 x 12 + 12 5 9 + 9 x 15)  

Total surface area = 2(180+108+135)

Total surface area = 2( 423)

Total surface area =  = 846 feet…………..(2)  

Finding the area of the door:

Area of door = area of rectangle = length x width

Substituting the values,

area of door= 3 x 7 = 21 feet……………(3)

Substituting (2) and (3) in (1)

Area that  is require paint = 846 – 21 = 825 feet

3 0
3 years ago
CAN SOMEONE PLS HELP ILL GIVE YOU BRAINLIST!! I DONT UNDERSTAND IT .
Harman [31]

Answer:

m∠P = 82°

m∠Q = 49°

m∠R = 49°

Step-by-step explanation:

<em>In the isosceles triangle, the base angles are equal in measures</em>

In Δ PQR

∵ PQ = PR

∴ Δ PQR is an isosceles triangle

∵ ∠Q and ∠R are the base angles

→ By using the fact above

∴ m∠Q = m∠R

∵ m∠Q = (3x + 25)°

∵ m∠R = (2x + 33)°

→ Equate them

∴ 3x + 25 = 2x + 33

→ Subtract 2x from both sides

∵ 3x - 2x + 25 = 2x - 2x + 33

∴ x + 25 = 33

→ Subtract 25 from both sides

∵ x + 25 - 25 = 33 - 25

∴ x = 8

→ Substitute the value of x in the measures of angles Q and R

∵ m∠Q = 3(8) + 25 = 24 + 25

∴ m∠Q = 49°

∵ m∠R = 2(8) + 33 = 16 + 33

∴ m∠R = 49°

∵ The sum of the measures of the interior angles of a Δ is 180°

∴ m∠P + m∠Q + m∠R = 180°

→ Substitute the measures of angles Q and R

∵ m∠P + 49 + 49 = 180

∴ m∠P + 98 = 180

→ Subtract 98 from both sides

∵ m∠P + 98 - 98 = 180 - 98

∴ m∠P = 82°

6 0
3 years ago
Read 2 more answers
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