Largest to Smallest:-
First lets write all the numbers down. 45, 94, 85, 490, 85, 93, 85, 035, 85.
035 is 35.
So lets order them now.
The biggest number is 490 and smallest is 35 (035).
490 - 94 - 93 - 85 - 85 - 85 - 85 - 035 (35)
The answer would be 16 S'mores and the limiting reactant would be the grahams.
(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)
Limiting reactant would be the reactant that runs out first.
Let's take your problem into account and see what we have:
48 marshallows
32 grahams (2 x 16 per pack)
45 chocolate pieces (5 x 15 pieces per bar)
Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.
The maximum yield of marshmallows is 48.
The maximum yield of chocolate is 45.
Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.
Answer:
23.54 m
Step-by-step explanation:
Applying
cos∅ = adjacent(A)/hypotenuse(H)
cos∅ = A/H................ Equation 1
make H the subject of the equation
H = A/cos∅............ Equation 2
Given: A = 15 m, ∅ = 25°
Substitute into equation 2
H = 15/cos25
H = 16.55 m
Also,
tan∅ = opposite(O)/Adjacent(A)
tan∅ = O/A............Equation 3
Make O the subject of the equation
O = Atan∅.......... Equation 4
Substituting into equation 4
O = 15(tan25°)
O = 6.99 m.
From the diagram,
The height of the goal post before snap = H+O
The height of the goal post before snap = 16.55+6.99
The height of the goal post before snap = 23.54 m
The answer is b)04 I did this on my test and got it correct
