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Stolb23 [73]
3 years ago
13

Factor using sum and product

Mathematics
2 answers:
solong [7]3 years ago
6 0

Answer:

(x+6)(x-5)

Step-by-step explanation:

The product is -30 and the sum is 1.

Factors of -30 are

-1  and 30

-2 and 15

-3 and 10

-5 and 6

-5 + 6 = 1

Nikitich [7]3 years ago
3 0

Answer:

Step-by-step explanation:

y=x^2+x-30

y=x^2-(6-5)x-30

y=x^2-6x+5x-30

y=x(x-6)-5(x-6)

y=(x-5)(x-6)

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Are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal.

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5k-7=-7<br> solve the equation to what is k
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Four plus a number times three is seventeen
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3 years ago
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Solve this equation: m- 10 = -6<br> m=
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4 years ago
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If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
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r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
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3 years ago
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