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ololo11 [35]
3 years ago
6

You are going to meet a friend at the airport. Your experience tells you that the plane is late 70% of the time when it rains, b

ut is late only 20% of the time when it does not rain.What is the probability that the plane will be late?
Mathematics
1 answer:
Feliz [49]3 years ago
6 0

Answer:

0.4

Step-by-step explanation:

Probability of rain = P(R)

Probability of late plane = P(L)

So, the probability of no rain = P(R')

Breaking it down

If it rains, 40% chance, P(R) = 0.4

That the plane would be late if it rains = 70% × 40%, that is, P(R n L) = 0.7 × 0.4 = 0.28, 28% of the total chance.

That the plane would be on time if it rains = 30% × 40%, that is, P(R n L') = 0.3 × 0.4 = 0.12, 12% of the total chance.

If it doesn't rain, 60% chance, P(R') = 1 - P(R) = 1 - 0.4 = 0.6

That the plane would be late if it doesn't rain = 20% × 60%, that is, P(R n L') = 0.2 × 0.6 = 0.12, 12% of the total chance.

That the plane would be on time if it doesn't rain = 80% × 60%, that is, P(R' n L') = 0.8 × 0.6 = 0.48, 48% of the total chance.

So, probability that the plane would be late = P(L) = P(R n L) + P(R' n L) = 0.28 + 0.12 = 0.4 = 40%

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Answer:

9x+4x^2-5y

Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

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Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

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OLEGan [10]

Answer:

The answer to your question is the letter A. 20 ft²

Step-by-step explanation:

Data

length of a side = 10 ft

length of the diameter = 10 ft

length of the radius = 5 ft

Process

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Area of the square = side x side

                                = 10 x 10

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Area of the circle = 78.5 ft²

3.- Calculate the remaining area

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\qquad\qquad\huge\underline{{\sf Answer}}

\textsf{Let's calculate the surface area of given right prism}

\textbf{Area of Triangles :}

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\textsf{Since there are two triangles, }

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\textsf{Now add them all :}

  • \textsf{120 + 160 + 200 + 192}

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