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Rama09 [41]
3 years ago
12

A peqch pie is made with 13 peaches, which are evenly distributed throughout the pie. If Joe ate one slice that contained exactl

y 5 peaches, what was the angle measure of the slice to the nearest tenth of a degree?
Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0

Answer:

138.5°

Step-by-step explanation:

Since the peach pie is a circle, we have a total angle of 360°.

We need to determine what fraction of the total pie of 13 peaches is the 5 peaches contained in Joe's slice.

This is number of peaches in Joe's slice/total number of peaches in pie = 5/13. To find the angle Joe's slice measures, we multiply 5/13 by 360°.

So, 5/13 × 360°

= 0.3846 × 360°

= 138.46°

≅ 138.5° to the nearest tenth of a degree

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Translating into symbols,

P(M)=.47

P(V)=.32

P(M&V)=.24

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The definition of conditional probability is

P(V | M) = P(V & M) / P(M)

P(V | M) =  .24 / .47 = .5106...

Answer: 0.51, second choice


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4 years ago
Which of the following rational exponent expressions is NOT simplified correctly as a radical expression?
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Answer:

What were the answers to the test?

Step-by-step explanation:

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3 years ago
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Alan is currently at a point that is 346.8 ft above sea level. He is planing to travel to Bombay beach, California, which is 236
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110.8 feet

Step-by-step explanation:

Find the difference in sea level by subtracting 236 from 346.8:

346.8 - 236

= 110.8

So, the difference in sea level is 110.8 feet

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3 years ago
A pyramid has a square base with sides 8" and a slant height of 5". total area =
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4 years ago
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12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely
AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is 6 a b^{2}(a+2)(2 a-1)

<u>Solution:</u>

Given, expression is 12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

We have to factorize the given expression completely.

Now, take the expression

12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

Taking b^2 as common term,

b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)

Taking "a" as common term,

b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)

Taking "6" as common term,

b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)

Splitting "3a" as "4a - a" we get,

b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)

\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}

Hence, the factored form of given expression is 6 a b^{2}(a+2)(2 a-1)

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3 years ago
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