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Katen [24]
3 years ago
7

12a^3b^2 +18a²b^2 – 12ab^2 Factor completely

Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is 6 a b^{2}(a+2)(2 a-1)

<u>Solution:</u>

Given, expression is 12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

We have to factorize the given expression completely.

Now, take the expression

12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

Taking b^2 as common term,

b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)

Taking "a" as common term,

b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)

Taking "6" as common term,

b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)

Splitting "3a" as "4a - a" we get,

b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)

\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}

Hence, the factored form of given expression is 6 a b^{2}(a+2)(2 a-1)

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<u>Answer:</u>

Below!

<u>Step-by step explanation:</u>

<u>We know that:</u>

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<u>Solution of Question A:</u>

<u>Percent of children: Total children/Total attendance</u>

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  • => 4/15
  • => 0.27 (Rounded to nearest hundredth)
  • => 0.27 x 100
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<u>Hence, the percent of children is about 27%.</u>

<u>Solution of Question B:</u>

<u>Percent of women: Total women/Total attendance</u>

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  • => 17/30
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<u>Solution of Question C:</u>

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<u>Percent of men: Total men/Total attendance</u>

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Hoped this helped.

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