Answer: Ali would need to drive 350 miles for the two plans to cost the same.
Step-by-step explanation:
This question can be solved by creating two equations using the information supplied in the question and then solving these simultaneously.
Let the cost be C.
Let the number of miles be M.
Let the initial payment be i.
Let the rate per mile driven be R.
Plan 1:
C = i+R×M
C = 70+0.60M ... equation 1
Plan 2:
C = i+R×M
C = 0+0.80M
C = 0.80M ...equation 2
Substituting equation 2 into equation 1:
0.80M = 70+0.60M
0.80-0.60M = 70
0.20M = 70
M = 70/0.20
M = 350 miles
Answer:
a. 
b. 
Step-by-step explanation:
a. 
A mixed fraction of the form 



b. 
A mixed fraction of the form 




Hence, the answer.
Answer: Theoretical- In a perfect world everything is a 50/50 chance and experimental is real world and the probability is not 50/50.
Step-by-step explanation:
Given the equation:

We will use the following rule to find the solution to the equation:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
From the given equation: a = 6, b = 7, c = 2
So,
![\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B7%5E2-4%5Ccdot6%5Ccdot2%7D%7D%7B2%5Ccdot6%7D%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B1%7D%7D%7B12%7D%3D%5Cfrac%7B-7%5Cpm1%7D%7B12%7D%20%5C%5C%20x%3D%5Cfrac%7B-7-1%7D%7B12%7D%3D-%5Cfrac%7B8%7D%7B12%7D%3D-%5Cfrac%7B2%7D%7B3%7D%20%5C%5C%20or%2Cx%3D%5Cfrac%7B-7%2B1%7D%7B12%7D%3D-%5Cfrac%7B6%7D%7B12%7D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cend%7Bgathered%7D)
So, the answer will be option B) x = -1/2, -2/3