The maximum number from integer N can be determined using the following program written in Python, where comments are used to explain each line

#This prompts the user for input

num = input("Number: ")

#This iterates from 0 to 9

kount = [0 for x in range(10)]

# This iterates through the input, and updates the kount variable

for i in range(len(num)):

kount[int(num[i])] = kount[int(num[i])] + 1

# This next two lines initialize the greatest number

greatestNum = 0

multiplier = 1

# This iterates through the kount array

for i in range(10):

#The following is repeated while the current element is greater than 0

while kount[i] > 0:

#This generates the greatest number

greatestNum = greatestNum + ( i * multiplier )

kount[i] = kount[i] - 1

multiplier = multiplier * 10

#This prints the greatest number

print(greatestNum)

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7 0

3 years ago

A 0.1 kg block of brass is cooled until it releases 56.4 J of heat. If the temperature of the block was 5 K initially, what is i

Zolol [24]

Answer:

3.5 K

Explanation:

When a sample of a substance releases heat energy, its temperature decreases according to the equation:

$Q=mC(T_f-T_i)$

where

Q is the heat energy released

m is the mass of the substance

C is the specific heat capacity

$T_i$ is the initial temperature

$T_f$ is the final temperature

For the block of brass in this problem, we have:

m = 0.1 kg is the mass

Q = -56.4 J is the heat energy released (negative since it is released)

C = 380 J/kg K is the specific heat capacity of brass

$T_i=5 K$ is the initial temperature

Solving for $T_f$ , we find the final temperature:

$T_f=T_i + \frac{Q}{mC}=5+\frac{-56.4}{(0.1)(380)}=3.5 K$

5 0

3 years ago

Describe several guidelines for preventing relapse.

n200080 [17]

Answer:

Well it depends are you going back to doing something that is bad for you, Then you need to try your hardest to not going back to doing it.

Explanation:

5 0

3 years ago