The Gibbs free energy ΔG for the vaporisation of 2-methylbutane, in KJ/mol is 8.24 KJ/mol
<h3>Data obtained from the question </h3>
- Enthalpy change (ΔH) = 25. 22 KJ/mol
- Change in entropy (ΔS) = 84.48 J/Kmol = 84.48 / 1000 = 8.448×10¯² KJ/Kmol
- Temperature (T) = 201 K
- Gibbs free energy (ΔG) =?
<h3>How to determine the Gibbs free energy </h3>
The Gibbs free energy for the reaction can be obtained as follow:
ΔG = ΔH – TΔS
ΔG = 25.22 – (201 × 8.448×10¯²)
ΔG = 25.22 – 169.8048
ΔG = 8.24 KJ/mol
Thus, the ΔG for the reaction is 8.24 KJ/mol
Learn more about Gibbs free energy:
brainly.com/question/9552459
<h3>
Answer:</h3>
Any x value that makes the denominator equal to 0
<h3>
Explanation:</h3>
Rational Functions
The quotient of two functions can be rewritten as a rational function. All rational functions have discontinuities in the domain where the denominator equals 0. For this to make sense, remember that anything divided by 0 is undefined.
Examples
To show this idea, I will use the example
. For this rational function or quotient of two functions, the x value -3 is not included in the domain. This is due to the fact that when x=-3, the denominator is equal to 0. Thus, the function is undefined at this value.
C. it’s the only example of procrastination while the rest are willingly studying