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Grace [21]
3 years ago
8

Couldn't fit the whole graph but someone please help im so confused ​

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0
(2,0) is the correct answer
You might be interested in
A rope 33cm long has a mass of 561g. What is the mass of 13cm of this rope?
Digiron [165]

Answer:

221g

Step-by-step explanation:

561g divided by 33cm is how much 1 cm of rope would be so then you multiply that amount by 13

8 0
4 years ago
Does every number have two square roots?​
Paha777 [63]

Answer:

no

Step-by-step explanation:

i think no because negative numbers dont have real square roots

6 0
3 years ago
Pls answer clearly , just the answer i dont need explenation:) please <3
lawyer [7]

Answer:

option D

Step-by-step explanation:

5 0
2 years ago
Helppp meee pleasssseee!!!
aivan3 [116]

Answer:

19°

Step-by-step explanation:

Set up the equation (triangles add up to 180 degrees)(Right angles are 90 degrees).

39 + 90 + 2x + 13 = 180

142 + 2x = 180

2x = 38

x = 19

5 0
3 years ago
Read 2 more answers
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

X = 340.1

Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
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