Answer:
I guess that you want to calculate the difference between the annual healt care costs in 1950 and today.
The equation is:
C(x) = $620*(1.082)^x
in 1950, we have x = 0 (because is the initial year)
then the cost is:
C(0) = $620*1 = $620.
Now, today, in 2020, we have:
x = 2020 - 1950 = 70
then we have:
C(70) = $620*(1.082)^70 = $154,276.7
So, according to this equation, te difference is:
$154,276.7 - $620 = $153,656.6
Answer:
I think it might be 6
Step-by-step explanation:
You should probably wait for another answer, I did this in Math last year so I think it's 6 but I can't really remember sorry ):
4
(
x
−
2
)
=
2
(
x
−
4
)
+
2
x
Step 1: Simplify both sides of the equation.
4
(
x
−
2
)
=
2
(
x
−
4
)
+
2
x
(
4
)
(
x
)
+
(
4
)
(
−
2
)
=
(
2
)
(
x
)
+
(
2
)
(
−
4
)
+
2
x
(Distribute)
4
x
+
−
8
=
2
x
+
−
8
+
2
x
4
x
−
8
=
(
2
x
+
2
x
)
+
(
−
8
)
(Combine Like Terms)
4
x
−
8
=
4
x
+
−
8
4
x
−
8
=
4
x
−
8
Step 2: Subtract 4x from both sides.
4
x
−
8
−
4
x
=
4
x
−
8
−
4
x
−
8
=
−
8
Step 3: Add 8 to both sides.
−
8
+
8
=
−
8
+
8
0
=
0
