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wel
3 years ago
12

Which is greater than 5/6

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0
6/6 is greater than 5/6

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Solve the system of equations 5x-2y=88 3x+4y=58 show all work
diamong [38]
The given equations are:

5x - 2y = 88
3x + 4y =  58

Multiplying the 1st equation by 2, we get the new set of equations as:

10x - 4y = 176
3x + 4y = 58

Adding the two equations, we get:

10x - 4y + 3x + 4y = 176 + 58
13x =234
x =  18

Using the value of x in 1st equation, we get:

5(18) - 2y = 88
- 2y = 88 -5(18)
-2y = -2
y = 1

So, the solution of the equation is (18, 1)

6 0
3 years ago
Read 2 more answers
Dan has some marbles
Andreyy89
A. Frank has 24 marbles. I found this because Dan has 15 and total is 63 so subtract 63-15= 48. 48 divided by 2 people, which are Ellie ans Dan is 24. Dan has 24 marbles.


3 0
3 years ago
21 - 3 + 8 or -14 + 31 - 6
sergejj [24]

Answer:21-3+8=26

-14+31-6=11

Step-by-step explanation:

3 0
3 years ago
A gumball machine has 220 red gumballs. If the red gumballs are 50% of the total number of gumballs, how many gumballs are in
JulijaS [17]
Answer:

440

Explanation:

If 50% of the total gum balls are red which is 220, then the other 50% is 220.
5 0
3 years ago
Read 2 more answers
Patrick went cycling one weekend.
Margarita [4]
For this question, it would be most effective to use an algebraic expression to more easily show what the question is asking. If we use the variable "k" to show the distance in km that he cycled on Sunday, we know that the amount he cycled on Saturday equals k + 12, and the amount that he cycled on the weekend should be the amount of Saturday plus the amount of Sunday. If we write this as an equation we say:
k + k + 12 = 38
=> 2k + 12 = 38
Now we can just rearrange and solve for k:
=> 2k = 26
=> k = 26/2 = 13
Therefore Patrick cycled 13km on Sunday
To solve the answer, we just add 12km to the value for Sunday like so:
12 + 13 = the amount he cycled on Sunday
Hope this helped, remember to please try and understand the maths as well as the answer :))
8 0
3 years ago
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