Answer:
<u>Given :</u>
length offshore = CS=√(1+X^2)
Cable charged = 5000√(1+X^2)
onshore length = 4-X
laying cost = 3000(4-X)
total cost:
C=5000√(1+X^2) +3000(4-X)
DC/DX
= [5000*(0.5)*2X/{√(1+X^2)}]-3000=0... for optimum
5000X=3000√(1+X^2)
25X^2=3+3X^2
22X^2=3
X=√(3/22)
= 0.3693 miles
So, it would be laid offshore to S in a manner that
BS=X=0.3693 miles
Onshore=4-0.3693
=3.6307 miles
The answer to these blanks are :
1. 6 (m)
2. 1 (s)
3. 0 (m)
4. 4 (s)
So find g(0) and g(3)
G(0) = 0^2 -5(0) +3 = 3
And g(3) = 3^2 - 5(3) +3 = 9 - 15 + 3 = 3 so there is no change in g(x) for that interval.
H(0) = 8(0) + 10 = 10
And h(3) = 8(3) + 10 = 34
So the change in h(x) for that interval is 24.
Answer:
The answer to your question is $9.5
Step-by-step explanation:
Data
Large pizza = L
Medium pizza = m
Write equation for both situations
Situation 1 5L + 2m = 81.5
Situation 2 4L + 3m = 78.5
Solve the system of equation by elimination
Multiply situation 1 by -3 and situation 2 by 2
-15L - 6m = -244.5
8L + 6m = 157
-7L = -87.5
Solve for L L = -87.5/-7
L = $12.5
Substitute L in Situation 1 to find m
5(12.5) + 2m = 81.5
62.5 + 2m = 81.5
2m = 81.5 - 62.5
2m = 19
m = 19/2
m = $ 9.5
The prize of a medium pizza is $9.5
Answer:
70,110,110,110
Step-by-step explanation:
I'm Asian and I was less than 5 minutes
