Answer:
(-3,-5)
Step-by-step explanation:
If we move left j units : we subtract the x coordinate by the j units
If we move right j units : we add the x coordinate by the j units
If we move down j units : we subtract the y coordinate by the j units
If we move up j units : we add the y coordinate by the j units
so (-3, -5)
3q + 2 (q + 1) :Distribute
3q + 2q + 1 :Combine like terms
<em><u>5q + 1</u></em>
Answer:
For Question 3, all you have to do is subtract 5 from both sides of the equation, then divide by -3, which will leave you with 5 as the answer.
-3x + 5 = -10
-3x = -15x
x = 5
(-3, 0) is a solution to given equation
(-6, -1) is a solution to given equation
<em><u>Solution:</u></em>
<em><u>Given that equation is:</u></em>
![y = \frac{1}{3}x + 1](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B3%7Dx%20%2B%201)
<h3><em><u>
Option 1</u></em></h3>
(-3, 0)
Substitute x = -3 and y = 0 in given equation
![0 = \frac{1}{3} \times -3 + 1\\\\0 = -1 + 1\\\\0 = 0](https://tex.z-dn.net/?f=0%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%20-3%20%2B%201%5C%5C%5C%5C0%20%3D%20-1%20%2B%201%5C%5C%5C%5C0%20%3D%200)
Thus (-3, 0) is a solution to given equation
<h3><em><u>
Option 2</u></em></h3>
(-9, -1)
Substitute x = -9 and y = -1 in given equation
![-1 = \frac{1}{3} \times -9 + 1\\\\-1 = -3 + 1\\\\-1 \neq -2](https://tex.z-dn.net/?f=-1%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%20-9%20%2B%201%5C%5C%5C%5C-1%20%3D%20-3%20%2B%201%5C%5C%5C%5C-1%20%5Cneq%20%20-2)
Thus (-9, -1) is not a solution to given equation
<h3><em><u>
Option 3</u></em></h3>
(-6, -1)
Substitute x = -6 and y = -1 in given equation
![-1 = \frac{1}{3} \times - 6 + 1\\\\-1 = -2 + 1\\\\-1 = -1](https://tex.z-dn.net/?f=-1%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%20-%206%20%2B%201%5C%5C%5C%5C-1%20%3D%20-2%20%2B%201%5C%5C%5C%5C-1%20%3D%20-1)
Thus (-6, -1) is a solution to given equation
Answer:
3 not the right anwser
Step-by-step explanation: