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3 years ago

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Mathematics

2 answers:

Anestetic [448]3 years ago

6 0

Find multiples of 30 and 40:

30: 30, 60, 90, 120, 150

40: 40, 80, 120, 160

The least common multiple is 120, so every 120 minutes they willl both ring.

1 hour = 60 minutes:

120/60 = 2 hours.

The bells ring together every 2 hours.

8 + 2 = 10 am

10 + = 12pm

12 + 2 = 2 pm

The bells will ring together at am, 12 pm and 2 pm.

quester [9]3 years ago

6 0

Answer:

<h2><u>Solution </u><u>:</u><u>-</u></h2>

At first common multiple of 30 an 40

$\sf \to \: 30 = 30,60,90,120$

$\sf \to \: 40 = 40,80,120$

Common Multiple = 120

Time taken = 120/60 = 2 hrs

Now,

8.00 + 2 = 10.00 am

10.00 + 2 = 12.00 noon

12.00 + 2 = 2.00 pm

$\\$

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Answer:

5 m

Step-by-step explanation:

Use the volume formula, V = lwh

Plug in the volume, width, and height, then solve for l (the length)

V = lwh

70 = (l)(2)(7)

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6 0

3 years ago

Read 2 more answers

Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.

Semmy [17]

Answer:

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

$p=2(l+w)$

where

$p$ is the perimeter

$l$ is the length

$w$ is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so $l=\frac{2}{x+1}$ and $w=\frac{5}{x^2-1}$ .

Replacing values:

$p=2(l+w)$

$p=2(\frac{2}{x+1} +\frac{5}{x^2-1})$

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula $a^2-b^2=(a+b)(a-b)$ where $a$ is the first term and $b$ is the second term. We can infer that $a=x^2$ and $b=1^2$ . So, $x^2-1=(x+1)(x-1)$ . Replacing that: