The 3rd or 1st one I'm not sure which one but u have an idea of what it might be
Answer:
let difference be x
Step-by-step explanation:
you can solve for x by keeping the 2 statesments as conditions.
then you solve for both equations together by adding subtracting or multiplying.
eg: let x be the number.
the. proceed with conditions as equations
then solve
then your answer is here
Answer:
yes
Step-by-step explanation:
There are several ways to go at this.
My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.
Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.
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You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.
(((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0
The value of h(5) is zero, so x-5 is a factor of h(x).
Answer:
YES
Step-by-step explanation:
$157+$210+$377+$145=$889
$695+$95=$790
Leftover
$889-$790 =$99
he would have $99 leftover
3^2(6-2)*(4-6)/3
=(9*4)*(-2/3)
=36*(-2)/3
= -72/3
= -24 (answer)