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Answer:
A. 15
Step-by-step explanation:
To solve this you need to compare the lengths given to you in the question statement.
Because the lines originate from a single point, they're like triangles. We can easily see a triangle AGF and a triangle ADE, right?
Both triangles are similar triangles, so we can see triangle ADE as a larger version of angle AGF.
They give you the dimension of A F and A E (through A F + F E) to establish a ratio... and they give you A G, asking for A D.
So, A F = 16, A E = 20 (16 + 4), A G = 12.
Since A D is to A G what A E is to A F, we can easily make the following cross-multiplication:
So, A D = (A G * A E)/A F
A D = (12 * 20) / 16 = 15
Answer:
The numbers needed to fill each box are in the image attached
Step-by-step explanation:
The probability of the coin landing on heads is 2/7, so the probability of it landing on tails is 1 - 2/7 = 5/7
The probability of landing heads 2 times is:
P = (2/7) * (2/7) = 4/49
The probability of landing heads and then tails is:
P = (2/7) * (5/7) = 10/49
The probability of landing tails and then heads is:
P = (5/7) * (2/7) = 10/49
The probability of landing tails 2 times is:
P = (5/7) * (5/7) = 25/49
The numbers needed to fill each box are in the image attached.
