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trapecia [35]
3 years ago
8

a stack of sheets of tissue paper is about 2.5 inches high. each sheet is about 0.01 inch thick. how many sheets are in the stac

k?show your work.
Mathematics
1 answer:
damaskus [11]3 years ago
4 0

Answer:

Step-by-step explanation:

2.5 / 0.01 = 250 sheets in the stack....just a little division problem....thank god for calculators...lol

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A toy box has a volume of 30 cubic feet. It is 5 feet wide And 2 feet long. What is the height of the toy box
otez555 [7]
V = a * b * c
V = 30 
a = 5
b = 2 
c = ?
30 = 5*2*c
30 = 10*c
c = 30/10 = 3
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What is 2 2/5 times 3 1/4
Naddik [55]

Answer:

7 4/5

Step-by-step explanation:

2 2/5 = 12/5

3 1/4 =  13/4

12/5 x 13/4 = 156/20 = 7 16/20

7 16/20 / 4 = 7 4/5

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A jewelry maker has 24 jade beads and 30 teak beads.What is the greatest number of necklaces she can make? How many beads of eac
gulaghasi [49]

Jewelery maker has

24 jade beads

30 teak Beads

She has to make necklaces with each necklace having the same number of beads

So we need to find the highest common factor for both 24 and 30

The factors for both numbers are as follows

24 -1,2,3,4,6,8,12,24

30 - 1,2,3,5,6,10,15,30

The highest common factor for both is 6

The greatest number of necklaces she can make is 6

Number of jade beads - 24/6 = 4 jade beads

Number of teak beads - 30/6 = 5 teak beads

So each necklace will have 4 jade beads and 5 teak beads

6 0
3 years ago
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Which polygon will NOT tessellate a plane?
Rufina [12.5K]

Step-by-step explanation:

the answer is regular octagon

i think

7 0
3 years ago
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

Apply substitution to get

y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0
3 years ago
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