V = a * b * c
V = 30
a = 5
b = 2
c = ?
30 = 5*2*c
30 = 10*c
c = 30/10 = 3
c = 3
Answer:
7 4/5
Step-by-step explanation:
2 2/5 = 12/5
3 1/4 = 13/4
12/5 x 13/4 = 156/20 = 7 16/20
7 16/20 / 4 = 7 4/5
Jewelery maker has
24 jade beads
30 teak Beads
She has to make necklaces with each necklace having the same number of beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are as follows
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
Step-by-step explanation:
the answer is regular octagon
i think
Answers:
a = -6/37
b = -1/37
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Explanation:
Let's start things off by computing the derivatives we'll need

Apply substitution to get

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.
The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero
a-6b = 0
a = 6b
At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)
-6a -b = 1
-6(6b) - b = 1 .... plug in a = 6b
-36b - b = 1
-37b = 1
b = -1/37
Use this to find 'a'
a = 6b
a = 6(-1/37)
a = -6/37