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professor190 [17]
4 years ago
10

What is the minimum value for h(x)=x^2−16x+60? Enter your answer in the box.

Mathematics
1 answer:
klemol [59]4 years ago
3 0

Answer:

minimum value is -4

Step-by-step explanation:

image is inserted above

yiu can comment down if you have any doubts

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A dance CD has 5 songs on it - 2 are slow, and 3 are fast. When the DJ at a dance plays a song it is not played again. All songs
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<span>Combinations: 5!/2!3!=10

</span>possibility: 1/10 = 2/20

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Question 7 ❤️ this is almost due and I need some help with question 7! Thanks
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Those are your answers.
3 0
4 years ago
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The triangle below has an area of 12 units
goblinko [34]

Answer:

please I don't understand your question

6 0
3 years ago
2. Select each correct answer. More than one answer may be correct.
blagie [28]

Answer:

a wetland ecosystem 500 meters the farm

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8 0
3 years ago
Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2). Find the coordinates of the center of th
balandron [24]
The answer:

the main formula of the circle's equation is 
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius

if a point A(x', y') passes through the circle, so the equation of the circle can be written as 
(x'-a)²+ (y'-b)² = R², and that is  a main formula.


<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²

and we know that R= OA = OC= OB, 
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies

x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)²  so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
 -5= -2x -4y, when x = -3 /2   we obtain y = 2

the center is C(-3/2, 2)
7 0
4 years ago
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