Question

The table shows the probabilities of winning or losing when the team is playing away or is playing at home.

Answer 1

Answer:

• Use numbers from respective cells of the table for calculations

a) Are the events 'winning' and 'playing at home' independent?  

• p(winning and playing at home) = 0.56
• p(winning)*p(playing at home) = 0.8*0.7 = 0.56

Since the probabilities are same, the events are independent

b) Are the events "losing" and "playing away" independent?

• p(losing and playing away) = 0.06
• p(losing)*p(playing away) = 0.2*0.3 = 0.06

Since the probabilities are same, the events are independent

Answer 2

ANSWER:

[i] P(winning & playing at home) = 0.56

P(winning) × P(playing at home) = 0.8 × 0.6

• 0.56

As they are same, so it is independent.

[ii] P(losing & playing away) = 0.06

P(losing) × P(playing away) = 0.3 × 0.2

• 0.06

As they are also same, so it is also independent.