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lisabon 2012 [21]
3 years ago
8

The table shows the probabilities of winning or losing when the team is playing away or is playing at home.

Mathematics
2 answers:
topjm [15]3 years ago
5 0

Answer:

  • <em>Use numbers from respective cells of the table for calculations</em>

a) <u>Are the events 'winning' and 'playing at home' independent</u>?  

  • p(winning and playing at home) = 0.56
  • p(winning)*p(playing at home) = 0.8*0.7 = 0.56

Since the probabilities are same, the events <u>are independent</u>

b) <u>Are the events "losing" and "playing away" independent</u>?

  • p(losing and playing away) = 0.06
  • p(losing)*p(playing away) = 0.2*0.3 = 0.06

Since the probabilities are same, the events <u>are independent</u>

MrRissso [65]3 years ago
4 0

ANSWER:

[i] P(winning & playing at home) = 0.56

P(winning) × P(playing at home) = 0.8 × 0.6

  • 0.56

<u>As they are same, so it is independent</u>.

[ii] P(losing & playing away) = 0.06

P(losing) × P(playing away) = 0.3 × 0.2

  • 0.06

<u>As they are also same, so it is also independent</u>.

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