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hammer [34]
2 years ago
10

the credit remaining on a phone card in dollars is a linear function of the total calling time made with the card in minutes. Th

e remaining credit after 30 minutes of calls is $15.20 and the remaining credit after 47 minutes of calls is $12.48 what is the remaining credit after 51 minutes of calls ​
Mathematics
1 answer:
Advocard [28]2 years ago
8 0

Answer:

he credit remaining on a phone card (in dollars) is a linear function of the

total calling time made with the card (in minutes), as shown in the figure below.

The remaining credit after 45 minutes of calls is $22.80 , and the remaining

credit after 64 minutes of calls is $19.76.

What is the remaining credit after 73 minutes of calls?

;

Not sure what figure you are referring to, write an equation from the given values:

Assign the values as follows

x1 = 45; y1 = 22.80

x2 = 64; y2 = 19.76

:

Find the slope (m) using the formula: m = %28y2-y1%29%2F%28x2-x1%29

m = %2819.76-22.80%29%2F%2864-45%29 = %28-3.04%29%2F%2819%29

m = -.16

:

Write the equation using the point/slope formula: y - y1 = m(x - x1)

y - 22.80 = -.16(x - 45)

y - 22.80 = -.16x + 7.2

y = -.16x + 7.2 + 22.80

y = -.16x + 30

;

Use this equation to find the credit (y) when minutes (x) = 73

y = -.16(73) + 30

y = -11.68 + 30

y = $18.32; credit after 73 minute of calls

:

:

That you can also see the original value of the phone card: x=0, y = $30

;

:

Did this help you understand what's going on here? Any questions

Step-by-step explanation:

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cestrela7 [59]

Answer:

x= 8

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Step-by-step explanation:

|x+1| /3 = 3

|x+1| = 9

|x| + |1| = 9

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4 0
2 years ago
Patti has two glue sticks that are partially used. One has 1/5 left, and one has 3/10 left. Which glue stick has more glue?
marishachu [46]

Answer:

the one with 3/10 left has more

Step-by-step explanation:

because 1/5 is equal to 2/10 and 3/10>2/10

8 0
3 years ago
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This is (compound) probability: Picking two numbers from 1-10 and getting a multiple of 3 both times.
NemiM [27]

Answer:

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As their is only one for the probability is

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There are now 9 counters left in the bag.

You only want the even ones , which are 2 6 8 and 10 ( four has been taken out)

There are only four even counters in the bag of nine counters so the probability is

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As you want both of these to occur, you need to multiply them

1/10 x 4/9 = 49/90

Step-by-step explanation:

7 0
3 years ago
Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced
Sati [7]

Answer:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

Step-by-step explanation:

\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls},(denoted \:W_1, W_2, \:and\: W_3)

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and  its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

The tree diagram of this event is also attached.

6 0
3 years ago
Please help me PLEASE
Anettt [7]
B hope it helps SORRY IF IM WRONG
5 0
2 years ago
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