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hammer [34]
2 years ago
10

the credit remaining on a phone card in dollars is a linear function of the total calling time made with the card in minutes. Th

e remaining credit after 30 minutes of calls is $15.20 and the remaining credit after 47 minutes of calls is $12.48 what is the remaining credit after 51 minutes of calls ​
Mathematics
1 answer:
Advocard [28]2 years ago
8 0

Answer:

he credit remaining on a phone card (in dollars) is a linear function of the

total calling time made with the card (in minutes), as shown in the figure below.

The remaining credit after 45 minutes of calls is $22.80 , and the remaining

credit after 64 minutes of calls is $19.76.

What is the remaining credit after 73 minutes of calls?

;

Not sure what figure you are referring to, write an equation from the given values:

Assign the values as follows

x1 = 45; y1 = 22.80

x2 = 64; y2 = 19.76

:

Find the slope (m) using the formula: m = %28y2-y1%29%2F%28x2-x1%29

m = %2819.76-22.80%29%2F%2864-45%29 = %28-3.04%29%2F%2819%29

m = -.16

:

Write the equation using the point/slope formula: y - y1 = m(x - x1)

y - 22.80 = -.16(x - 45)

y - 22.80 = -.16x + 7.2

y = -.16x + 7.2 + 22.80

y = -.16x + 30

;

Use this equation to find the credit (y) when minutes (x) = 73

y = -.16(73) + 30

y = -11.68 + 30

y = $18.32; credit after 73 minute of calls

:

:

That you can also see the original value of the phone card: x=0, y = $30

;

:

Did this help you understand what's going on here? Any questions

Step-by-step explanation:

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Substitution is where we first Isolate one of the unknowns, express it in terms of the other unknown, and replace the isolated unknown with the other unknown in another equation. So that each time we only need to deal with one unknown. I think you'll get a better idea here:

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Since y is already isolated in (2), so we can skip the isolation step and continue to substitute.

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3 0
2 years ago
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

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ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

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Area 2:

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Therefore, the area of the shaded portion of the graph is

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