Okay. First simplify all the like terms (all the coefficients and all the variables).
When simplified it should give you:
5x-11
Y = -4x + 8
First you need to find the slope of the line.
The slope formula is m = y2-y1/x2-x1
If you plugged in the points it would be m = -4-4/3-1
so m = -8/2 = -4
so the slope is -4
now we need to write the equation of the line
for this u use point slope form
the formula for that is y-y2=m(x-x1)
so if you plug it in it would be:
y-(-4)=-4(x-3)
now you solve
y+4=-4x+12
y+4-4= -4x+12-4
y = -4x + 8
and now you have the slope of the line
I hope this helps! :)
Answer:
y=27.8
Step-by-step explanation:
- 8^2=17^2+16^2-2(16)(17)cosY
- 8^2-17^2-16^2/-2(17)(16)=cosY
- -481/-544=cosY
- 0.8842=cosY
- Y is about 27.8
Answer:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
Step-by-step explanation:
Jogging pants design Selling Price Cost
weekly production
Design A x₁ 2500 1750
Design B x₂ 2100 1200
1. z ( function is : )
z = 2500*x₁ + 2100*x₂ to maximize
First constraint weekly production
x₁ + x₂ ≤ 120
Second constraint Budget
1750*x₁ + 1200*x₂ ≤ 150000
Then the model is
z = 2500*x₁ + 2100*x₂ to maximize
Subject to
x₁ + x₂ ≤ 120
1750*x₁ + 1200*x₂ ≤ 150000
General constraints x₁ ≥ 0 x₂ ≥ 0 both integers
First table
z x₁ x₂ s₁ s₂ cte
1 -2500 -2100 0 0 0
0 1 1 1 0 = 120
0 1750 1200 0 1 = 150000
Using AtoZmath online solver and after 6 iterations the solution is:
z(max) = 256000 Php
x₁ = 10
x₂ = 110
