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Vilka [71]
2 years ago
11

Plzzzzzzzzzz helppppppppppppppppppp 4/5-1/4

Mathematics
2 answers:
Amanda [17]2 years ago
6 0

Answer:

11/20 is the answer

DaniilM [7]2 years ago
5 0
0.55
I’m sorry if it’s wrong but here you go!
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What is the slope of у>- 2х + 3
charle [14.2K]

Answer:

-2x

Step-by-step explanation:

Graph

y > −2x + 3

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

y = mx + b

Find the values of m and b using the form y = mx + b. m = −2

b = 3

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: −2

intercept: (0, 3)

Graph a dashed line, then shade the area above the boundary line since y is greater than

−2x + 3.

y > −2x + 3

8 0
3 years ago
PLEASE HURRY!! Will give brainliest!!
AURORKA [14]

Answer:

A. ("Mo worked more than 11 hours this week. ")

Step-by-step explanation:

Let d represent the value of hours Mo has worked.

d is more than 11 hours because Mo worked more than 11 hours

so it's safe to say...

d>11

5 0
3 years ago
Read 2 more answers
Given f (x) =2x-3 what is f(-15) <br><br> A. -16<br> B. -13<br> C. 7<br> D. 30
Murljashka [212]
Letter d is the answer.
5 0
3 years ago
Una persona camina 7 kilómetros hacia el norte, después 3 kilómetros hacia el este y, luego, 3 kilómetros hacia el sur. ¿A qué d
qaws [65]

Answer:

La persona está a 5 kilómetros con respecto al punto de partida.

Step-by-step explanation:

Considérese que la dirección norte coincide con el semieje +y y que la dirección este coincide con el semieje +x. A continuación, obtenemos las formas vectoriales equivalentes de cada afirmación:

(i) Una persona camina 7 kilómetros hacia el norte:

\vec r_{1} = 7\,\hat{j}\,[km]

(ii) Después 3 kilómetros hacia el este:

\vec r_{2} = 3\,\hat{i}\,[km]

(iii) Y luego, 3 kilómetros hacia el sur:

\vec r_{3} = -3\,\hat{j}\,[km]

El vector resultante de desplazamiento se construye a partir de la siguiente suma de vectores:

\vec R = \vec r_{1}+\vec r_{2} + \vec r_{3} (1)

\vec R = 3\,\hat{i} + 4\,\hat{j}\,[km]

Asumiendo que la distancia coincide con el desplazamiento resultante, calculamos la distancia con respecto al punto de partida mediante el Teorema de Pitágoras:

\|\vec R\| = \sqrt{3^{2}+4^{2}}

\|\vec R\| = 5\,km

La persona está a 5 kilómetros con respecto al punto de partida.

3 0
2 years ago
Solve the system of two linear inequalities graphically.
Sladkaya [172]

Answer:

See attachment

Step-by-step explanation:

Isolate y in the first inequality:

2x + 4y < -16\\4y < - 16 -2 x\\y < -4 -\frac{1}{2} x\\y < -\frac{x+8}{2} \\

Now, with both x and y inequalities found, graph it.

7 0
1 year ago
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