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Vilka [71]
3 years ago
11

Plzzzzzzzzzz helppppppppppppppppppp 4/5-1/4

Mathematics
2 answers:
Amanda [17]3 years ago
6 0

Answer:

11/20 is the answer

DaniilM [7]3 years ago
5 0
0.55
I’m sorry if it’s wrong but here you go!
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Hilary bought two new books for $5.25 each and three used books for $2.50 each. Shipping costs $5.00 total for the first two ite
KatRina [158]

Answer:

26.75

Step-by-step explanation:

7 0
3 years ago
the graduate record exam (gre) is a standardized test which serves as an admission requirement for many graduate schools, and ha
True [87]

main answer : the normal distribution of given graduate record  exam is 1,A(1)=0.3413

supporting answer:Because of its flared shape, a graphical representation of a normal distribution is sometimes referred to as a bell curve. The precise shape varies depending on the population distribution, but the peak is always in the middle and the curve is always symmetrical. The mean, mode, and median of a normal distribution are all the same.

body of the answer: given that x₁=mean+standard deviation

                                     given mean₁=462

                                                standard deviation =119

  x₁=462+119=581

  z₁=581-462/119=1

  A(1)=0.3413

given mean₂=584

        standard deviation=151

x₂=584+151

   =735

z₂=735-584/151

  =1

A(1)=0.3413

final answer:there fore both scores are normal

to learn more about normal distribution link

brainly.com/question/23418254#:~:text=Expert%2DVerified%20Answer&text=Most%20values%20are%20close%20to%20the%20mean%20value.,curve%20called%20the%20normal%20curve.

#SPJ4

6 0
1 year ago
Drag the correct number of pieces to show how to find the area of the shaded figure in two different ways. Pieces can be rotated
AURORKA [14]

Answer:forgot to add sin a = -5

Step-by-step explanation:

3 0
3 years ago
What is the answer for this equation
Allushta [10]

i guess we'll never know *dance montage*

6 0
3 years ago
Read 2 more answers
How to do this question
Dafna11 [192]

Answer:

0

Step-by-step explanation:

Given:

f(x) = \begin{cases} -x -2 &, &x < 0 \\ x &, &0 \leqslant  x < 3 \\ x^2 -1 &, &3 \leqslant x \end{cases}

Solving for f(0):

f(0) = x \text{ when } x = 0 \\ f(0) = 0

6 0
3 years ago
Read 2 more answers
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