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Sauron [17]
3 years ago
10

A board game has 25 cards. Each card is printed with a number from 1 through 25. Sameer shuffled the cards, and then selected 1

card.
What is the probability that Sameer selected a card with a number less than 4 or a multiple of 9?

Enter your answer as a fraction, in simplified form, in the box

__________
Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0
The answer would probley be 2 or 18 if im wrong sorry
hoa [83]3 years ago
6 0
The answer 1/5. (The options are 9, 18, 3, 2, and 1.)
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Can someone please help me with number 2 thank you!
Natasha2012 [34]

Answer:

Number 2 is 32

Step-by-step explanation:

advanced calculator!

Hope it helps

5 0
4 years ago
A hypothesis test is conducted with a significance level of 10%. The alternative hypothesis states that more than 15% of a popul
Drupady [299]

Answer:

D. We cannot conclude that more than 15% of the population has at least one sibling.

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of people who has at least one sibling

\hat p estimated proportion of people who has at least one sibling

p_o=0.15 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of people who has at least one sibling is more than 0.15:  

Null hypothesis:p\leq 0.15  

Alternative hypothesis:p > 0.15  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Let's assume that the calculated value for this case is z_{calc}

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z> z_{calc})=0.27  

So the p value obtained was a very high value and using the significance level given \alpha=0.1 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the proportion of people who has at least one sibling is not significanlty higher than 0.15.

So then the best answer for this case would be:

D. We cannot conclude that more than 15% of the population has at least one sibling.

6 0
3 years ago
Suppose that 75 percent of the people in a certain metropolitan area live in the city and 25 percent in the suburbs. If 1200 peo
juin [17]

Answer:

31/40

Step-by-step explanation:

Probability is given by number of possible outcomes ÷ number of total outcomes

Number of possible outcomes = 270, number of total outcomes = 1200

Probability (the number of people from the suburbs attending the concert is 270) = 270/1200 = 9/40

Probability (the number of people from the suburbs attending the concert is fewer than 270) means that the number of people from the suburbs attending the concert is not 270 = 1 - 9/40 = (40-9)/9 = 31/40

5 0
3 years ago
Please help and no links to stuff bc they don't work ​
mr_godi [17]

5 inches

Hope this helps

5 0
3 years ago
Help me please ASAP i need your help<br><br> Converting Repeating Decimals to Rational Numbers
Free_Kalibri [48]
A repeating is always a rational number there is no way to convert them just make sure they are repeating in a pattern
8 0
4 years ago
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