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sergey [27]
3 years ago
14

If the school supply kit reqularly cost 25 how much does it cost in dollars after the 20 discount

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer: $20

Step-by-step explanation:

20% of 25 is 5

You can figure that out by writing 20/100 (percents are out of 100)

Simplified 20/100 would be 1/5

so we are finding 1/5 of 25

1/5 x 25/1 = 25/5 or 5

So the discount is $5

$25 - $5 is $20

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How much fruit punk will each kid get if 4 kids share 6/7 of a gallon of fruit punch? Show your work. Which answer is correct?
Assoli18 [71]
Divide the 6/7  of a gallon by 4

(6/7) ÷ 4
flip and multiply
(6/7) × (1/4) = 6/28
simplify
6/28 = 3/14 gallon for each kid
4 0
4 years ago
Read 2 more answers
Lizzie bought 0.8 kg of pears at €1.90 per kilogram and 1.4 kg of apples. The total cost €4.46. What was the price per kilogram
scoundrel [369]

Answer:

The the cost of 1 kg apples =  € 2.1

Step-by-step explanation:

The amount of pears bought by Lizzie  = 0.8 kg

The amount of apple bought by Lizzie  =  1.4 kg

Total amount paid  =  €4.46

Now, the cost of 1 kg pears =  €1.90 per kg

So, the cost of 0.8 kg pears  = 0.8  x (1.90)  =  €1.52

Now, let the cost of 1 kg apples =  € m

So, the cost of 1.4 kg apples  = 1.4 x ( € m)  = 1.4 m

So, the total amount = Cost of Apples + Cost of Pears

⇒                    €4.46   =  €1.52   +  1.4 m

or, 1.4 m = 4.46  - 1.52  = 2.94

⇒ m = 2.94/1.4 = 2.1

or, m = 2.1

Hence, the the cost of 1 kg apples =  € 2.1

7 0
4 years ago
Has one of your eyelash wishes ever came true?
lesantik [10]
Nope never made one
3 0
3 years ago
Read 2 more answers
Gary ate 41/50 of his candy bar. What percent of the candy bar did Gary eat?
Anton [14]
The answer is 0.82 so he eat 82 percent of the candy bar 

3 0
3 years ago
Solve :- Ques 5 ) (a) .
svp [43]

Answer:

Hey There!

Let's solve...

We have

\angle \: odb =  \angle \: cao \\  \\  \angle \: dbo =  \angle \: aco \\  \\

Using AA Criterion of Similarity we have

\triangle \: obd \:  -  \triangle \: oac \\  \\

This implies that

\frac{od}{ob} =  \frac{oa}{oc} \to \frac{6}{3 + 2 } \: or \:  \frac{6}{5} =  \frac{oa}{oc}    \\  \\  \to \: oa =  \frac{6}{5} oc

Now,

ab = ao - bo \\  \\  =  \frac{6}{5}oc - bo =  \frac{6}{5}(od - oc) \\  - bo \\  \\  =  \frac{6}{5}(6 + 4cm) - 5cm \\  \\  = 7cm

Note:Every letters should be in capital, i don't have any option here so i can't do.

<h2>I hope it is helpful to you...</h2><h3>Cheers!_________</h3>
5 0
3 years ago
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