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2 years ago

What is the equation of this line?

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

7 0

Answer:

Y=4

Step-by-step explanation:

The line is horizontal, which means that variable would be 4. The line starts at 4, which mean the equivalent of the variable is 4.

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Yo can anybody please help me answer this question

KIM [24]

Answer:

Step-by-step explanation:

by the definition of an isocoles triangle, defined by having two congruent sides, (p-s, r-s), angles SPR and SRP are congruent. by the triangle sum theorem, (internal angles + to 180˚) 90˚ + 2a = 180˚. 2a =90, a = 45

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2 years ago

A shoe store uses a 50 percent markup for all of the shoes it sells. What should be the selling price of a pair of shoes that ha

Margarita [4]

Answer:

85.5

Step-by-step explanation:

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2 years ago

What is the relationship between 1 and 2? WILL GIVE BRAINLYEST.

netineya [11]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

10 points for answering!<br> What is the answer to 13, 14, and 15?

ki77a [65]

Step-by-step explanation:

$\implies\sf{ {x}^{2} = 144 } \\ \\ \implies\sf{ x = \pm \sqrt{144} } \\ \\ \implies\sf{ x = \pm 12 }$

$\implies\sf{ {x}^{2} = \dfrac{25}{289} } \\ \\ \implies\sf{ x = \pm \sqrt{ \frac{25}{289} } } \\ \\ \implies\sf{ x = \pm \frac{5}{17} }$

$\implies\sf{ {x}^{3} = 216 } \\ \\ \implies\sf{ x = \sqrt[3]{216} } \\ \\ \implies\sf{ x = 6 }$

4 0

2 years ago

Your friend claims that because each midsegment is half as long as the corresponding side of the triangle, the perimeter of the

AlexFokin [52]

Answer:
The claim is correct

Explanation:
Assume the given triangle ABC
perimeter of triangle ABC = AB + BC + CA ............> I

Now, we have:
D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1
E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2
DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3
perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:
perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> II

From I and II, we can prove that:
perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:
perimeter of midsegment triangle is half the perimeter of the original triangle.

Hope this helps :)

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2 years ago