Answer:
Step-by-step explanation:
Based on the two graphs I see at the bottom of the photo, you're looking at a quadratic function. The answer you put in is a linear equation.
Quadratic functions follow the form
, where a, b, and c can be either positive or negative constants.
The table says that the equation, when graphed, should start at the top, slide to the bottom, and then slide back up to the top. So a must be positive.
c has to be -8 since it's the y-intercept.
So far, our equation is
. We'll need to plug in some points in order to work out what
and
are.
Let's use
as the first set of points, and
as the second set.

Now we have 2 equations with 2 unknowns. Solve for one variable:

Now substitute that into the second equation:

Now substitute the result into the first equation.

Now substitute our values back into the original equation:

Please let me know if this is correct.
Answer:
See below
Step-by-step explanation:
Expand it a bit to see:
= ![\sqrt[5]{ 2^5 * 7 * x^5 * x^5 * x * y^5 * y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%202%5E5%20%2A%207%20%2A%20x%5E5%20%2A%20x%5E5%20%2A%20x%20%2A%20y%5E5%20%2A%20y%5E3%7D)
=![2x^2y \sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=2x%5E2y%20%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Answer:
The experimental probability can be expressed in three ways:
Fraction Form: 3/6 or 1/2
Decimal Form: 0.5
Percent Form: 50%
Step-by-step explanation:
Experimental probability is expressed as:
<em>(Favorable outcomes) / (Total outcomes)</em>
The favorable outcome in this situation is blubbery muffins. There were 3 blueberry muffins sold, so this is the <u>numerator</u> of our fraction.
To find the total outcomes we add 3 + 3, which equals 6. This will be the <u>denominator</u> of our fraction.
The fraction used to express experimental probability will look like this: 3/6
We can further simplify this to 1/2.
3 ÷ 3 = 1
6 ÷ 3 = 2
To find a decimal, we divide 1 ÷ 2 = 0.5
Multiply this by 100 to get a percentage, 0.5 x 100 = 50%
Answer:
C
Step-by-step explanation:
X+y=8
2x^2-y=-5
elimination method means you link the 2 equations together to make one
these two already have y in the perfect form where you can cancel it out +y and -y so no need to perform any other action to a certain equation.. all you need to do is add them now
2x^2+x=3