I'm guessing the equation is 2x^2-3x=-5
If this is the case, then you need to set the equation to equal 0 by moving the -5 to the left side of it
2x^2-3x+5=0
The you can factor the equation
(2x-5)(x+1)=0
now solve for each factor
2x-5=0 is x=5/2x
x+1=0 is x=-1
For the first question
1/x-3, x cannot equal +3. As that would make the denominator 0.
For the second question.
Substitute f(x) into g(x) to get:
x^2 - 3
The area of a triangle can be determined by knowing 2 sides and their included angle of a certain triangle. Since both sides are equal, then they would just be denoted by a squared entity. This is done as follows:
A = x² sin∅
32 = x² sin (5*pi/6)
Make sure your calculator is in rad form.
32 = x² (1/2)
x = 8
Thus, each side is 8 cm.
Answer:
$18
Step-by-step explanation:
I did the following expressions:
1,350 / 75 = 18
1,080 / 60 = 18
<span>50+<span>24<span>6<span>x2
</span></span></span></span><span>=<span><span><span>300<span>x^2</span></span>+24/</span><span>6<span>x^2
the answer is </span></span></span></span><span>=<span><span><span>50<span>x^2</span></span>+4/</span><span>x^<span>2</span></span></span></span>
