3 years ago

Find the 15th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 2.

Mathematics

1 answer:

Alenkinab [10]3 years ago

6 0

Nose rkrbtje de donde salió la luz de

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<img src="https://tex.z-dn.net/?f=15%20%5Ctimes%2094%20-%2089%20%5Cdiv%205" id="TexFormula1" title="15 \times 94 - 89 \div 5" al

lakkis [162]

1410-89/5
1410-17.8= 1392.2

7 0

3 years ago

In triangle JKL, tan(b°) = 3/4 and cos(b°) =4/5. If triangle JKL is dilated by a scale factor of 1/2, what is sin(b°)?

zysi [14]

Answer:

$\sin (b^\circ)=\dfrac{3}{5}$ .

Step-by-step explanation:

It is given that,

$\tan (b^\circ)=\dfrac{3}{4}$

$\cos (b^\circ)=\dfrac{4}{5}$

If a figure is dilated, then the image is similar to the figure. It means the corresponding angles of figure and image are congruent.

So, the value of sin(b°) after dilation is equal to the value of sin(b°) before dilation.

We know that,

$\dfrac{\sin \theta}{\cos \theta}=\tan \theta$

$\dfrac{\sin (b^\circ)}{\cos (b^\circ)}=\tan (b^\circ)$

$\sin (b^\circ)=\tan (b^\circ)\times \cos (b^\circ)$

$\sin (b^\circ)=\dfrac{3}{4}\times \dfrac{4}{5}$

$\sin (b^\circ)=\dfrac{3}{5}$

Therefore, $\sin (b^\circ)=\dfrac{3}{5}$ .

5 0

4 years ago

The following system of equations is graphed below.

mafiozo [28]

Answer:

C) is the solution

Step-by-step explanation:

As the two equations have an intersection at (-5,1), which means they share the same point, then (-5 , 1 ) is the solution for the system.

5 0

3 years ago

Set these numbers from least to greatest <br><br> 2/3, -0.6, 0.65, 4/5

tensa zangetsu [6.8K]

Answer:

1. -0.6

2. 0.65

3. 2/3

4. 4/5

5 0

4 years ago

Read 2 more answers

(8:2). 4+{[3-2).2-5].4 expresoa numerica

GaryK [48]

4+{[3-2).2-5].4

1st proceder a la multiplicación ==> 4+{(6-4) -5}4

2nd Quitar los paréntesis ==> 4+{2-5}4==> 4+{-3}4

3rd multiplicación: 4+{-12}

4th = - 8

3 0

3 years ago