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marin [14]
3 years ago
15

Find the percent increase. From 32 teachers to 45 teachers.

Mathematics
1 answer:
qaws [65]3 years ago
4 0

Answer:

71.1

Step-by-step explanation:

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recall the equation for a circle with center (h,k) and radius r At what point in the first quadrant does the line with equation
Angelina_Jolie [31]

9514 1404 393

Answer:

  ≈ (3.578, 5.789)

Step-by-step explanation:

We can substitute for y and solve for x.

  (x -h)^2 +(y -k)^2 = r^2 . . . equation of a circle with center (h, k), radius r

  x^2 +(y -4)^2 = 4^2 . . . . . . the equation of the given circle

  x^2 +((0.5x +4) -4)^2 = 16

  (5/4)x^2 = 16

  x = 8/5√5 . . . . multiply by 4/5 and take the square root

  y = 0.5x +4

  y = 4/5√5 +4

The point of intersection is (8/5√5, 4+4/5√5), approximately (3.578, 5.789).

6 0
3 years ago
What do I do need help asp find the intercept
Vera_Pavlovna [14]

Answer:

y-intercept: 0

Step-by-step explanation:

Write it in slope-intercept form. Brainly removed my step-by-step explanation with lots of equations that took me a while to write on here so I'm just putting this for the explanation. Hope it suffices.

6 0
3 years ago
What’s the least common multiple of x^2-2x-15 and x^2+2x-3?
Ghella [55]

Answer:

\large\boxed{LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)}\\\boxed{=x^3-3x^2-13x+15}

Step-by-step explanation:

x^2-2x-15=x^2+3x-5x-15=x(x+3)-5(x+3)=(x+3)(x-5)\\\\\\x^2+2x-3=x^2+3x-1x-3=x(x+3)-1(x+3)=(x+3)(x-1)\\\\LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)\\\\=(x^2-2x-15)(x-1)\qquad\text{use FOIL}\\\\=(x^2)(x)+(x^2)(-1)+(-2x)(x)+(-2x)(-1)+(-15)(x)+(-15)(-1)\\\\=x^3-x^2-2x^2+2x-15x+15\qquad\text{combine like terms}\\\\=x^3+(-x^2-2x^2)+(2x-15x)+15\\\\=x^3-3x^2-13x+15

4 0
4 years ago
I’m so bad at this ughhhhhhhhhhhhhhhhhhh
Alexus [3.1K]

Answer:

a)6

b)v^2-u^2/2a

Step-by-step explanation:

a)Given that,

u=12

a= -6

s=9

We know that,

v^2=u^2+2as

or, v^2=(12)^2+2×(-6)×9

or,v^2=144-108

or,v^2=36

or, v=√36

∴v=6

         (Ans)

b)If ,v^2=u^2+2as

then, u^2+2as=v^2

or,2as=v^2-u^2

or, s=v^2-u^2/2a

∴s=v^2-u^2/2a

Hope ya find it helpful.. Thanks a lot...

6 0
3 years ago
Find the k, in (2x^2 - 3x + k)/ x-4
amid [387]
Answer could be this 2x^2 - 7x + k/ x in a fraction with x being the only thing at the bottom btw
7 0
4 years ago
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