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bagirrra123 [75]
3 years ago
9

Multiply 132.71 x 10 with the power of 2

Mathematics
2 answers:
alina1380 [7]3 years ago
8 0

Step-by-step explanation:

132.71 x 10 with the power of 2 = 13271

mestny [16]3 years ago
3 0
13,271 is the answer
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vazorg [7]

Answer: 12 - 3 = x

Step-by-step explanation:

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3 years ago
a glass jar has 64 chocolate. mark, dave and ralph will share the chocolate in the ratio of 1:1:2, how many chocolates will each
tia_tia [17]

Step-by-step explanation:

64/(1+1+2)

= 64/4

= 16

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mark = 1×16 = 16

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3 years ago
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A survey reports that 67% of college students prefer to drink more coffee during the exams week. If we randomly select 80 colleg
Akimi4 [234]

Answer:

The probability that at most 50 say that they drink coffee during exam week is 0.166.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of college students who prefer to drink more coffee during the exams week.

The probability of the random variable <em>X</em> is <em>p</em> = 0.67.

A random sample of <em>n</em> = 80 college students are selected.

The response of every students is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 80 and <em>p</em> = 0.67.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

np=80\times 0.67=53.6>10\\n(1-p)=80\times (1-0.67)=26.4>10

Thus, a Normal approximation to binomial can be applied.

X\sim N(np, np(1-p))

The mean of the distribution of <em>X</em> is:

\mu=np=80\times 0.67=53.6

The standard deviation of the distribution of <em>X</em> is:

\sigma=\sqrt{np(1-p)}=\sqrt{80\times 0.67\times (1-0.67)}=4.206

A Normal distribution is a continuous distribution. So, the probability at a point cannot be computed for the Normal distribution. To compute the probability at a point we need to apply the continuity correction.

Compute the probability that at most 50 say that they drink coffee during exam week as follows:

Apply continuity correction:

P(X\leq 50)=P(X

                 =P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 50 say that they drink coffee during exam week is 0.166.

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