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Katen [24]
3 years ago
6

Evaluate f+g^2-3g if f= 5 and g=2

Mathematics
2 answers:
timama [110]3 years ago
4 0

Answer:

3

Step-by-step explanation:

f + g^{2} - 3g

= 5 + 2^{2} - 3 * 2

= 5 + 4 - 3 * 2

= 5 + 4 - 6

= 9 - 6

= 3

Lady_Fox [76]3 years ago
3 0

Answer:

The answer world be 3.

Step-by-step explanation:

5 + 2² - 3(2) = 3

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Luke buys shares for £15.26 each they decrease in value by 3.5% work out the new share price
Murljashka [212]

Answer:

New price is $14.73 Per share

Step-by-step explanation:

(1 - 3.5%) × 15.26 = 14.7259

Round to the nearest hundreth

New share price = $14.73

6 0
2 years ago
g Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distrib
algol13

Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125

This means that n = 125, s = \frac{7320}{\sqrt{125}}

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

4 0
3 years ago
Determine whether the statement below is always, sometimes, or never true. two lines with positive slopes are parallel.
elena-s [515]
Always because according to my calculations 
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3 years ago
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Amy and her friends have $12.50 to spend on lunch. They agree to share a
Anastaziya [24]
Good luck, I am not sure how to solve the next part of the question

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What dose each part of the equation represent? pls help
AlekseyPX

Answer:

A, B and C are placeholders for constants. (x and y are variables)

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