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2 years ago

Evaluate f+g^2-3g if f= 5 and g=2

Mathematics

2 answers:

timama [110]2 years ago

4 0

Answer:

Step-by-step explanation:

f + $g^{2}$ - 3g

= 5 + $2^{2}$ - 3 * 2

= 5 + 4 - 3 * 2

= 5 + 4 - 6

= 9 - 6

= 3

Lady_Fox [76]2 years ago

3 0

Answer:

The answer world be 3.

Step-by-step explanation:

5 + 2² - 3(2) = 3

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hey guys i really need help with this is for the MOSL in my class how do i find the tax of a question

mylen [45]

How to tax things:

In this case, lets say the state tax is 7%.
Shen you buy something, lets say some shoes. For example lets say the price is 60.99
With the 7% tax, move the decimal point two times to the left: 7 -> .07
Multiply .07 by the total price

60.99 * .07 = 4.27
Then add this amount to the total price
60.99 + 4.27 = 65.26
This is how you tax

3 0

3 years ago

Read 2 more answers

F(x)=Tan^-1 (1)<br><br> PLEASE ANSWER! WILL GIVE BRAINLIEST

notka56 [123]

Answer:

−π

----

Step-by-step explanation:

Alright, archtan /

tan

−

(

)

is the inverse of tangent. Tan is

sin

cos

. Like the inverse of sin, the inverse of tan is also restricted to quadrants 1 and 4.

Knowing this we are solving for the inverse of tan -1. We are basically being asked the question what angle/radian does tan(-1) equal. Using the unit circle we can see that tan(1)= pi/4.

Since the "Odds and Evens Identity" states that tan(-x) = -tan(x). Tan(-1)= -pi/4.

Knowing that tan is negative in quadrants 2 and 4. the answer is in either of those two quadrants. BUT!!! since inverse of tan is restricted to quadrants 1 and 4 we are left with the only answer -pi/4.

5 0

2 years ago

Greta bought 3 lb and 4 oz of peanuts and shared 1 lb 12 oz with the class. what is the weight of the remaining peanuts ?

makkiz [27]

Answer:

1lb 8 oz

Step-by-step explanation:

Take 3 lbs and separate it into 48oz + 4 oz = 52 oz.

Same with the 1 lb 12 oz. 16 oz + 12 oz = 28.

Subtract 28 from 52 = 24 oz = 1 lb 8 oz.

Hope this helps.

5 0

3 years ago

An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airp

balu736 [363]

Answer:

r = 225 Mil/h speed of the airplane in still air

Step-by-step explanation:

Then:

d is traveled distance and r the speed of the airplane in still air

so the first equation is for a 4 hours trip

as d = v*t

d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)

Second equation the trip back in 5 hours

d = 5 * ( r - 25 ) (2)

So we got a system of two equation and two unknown variables d and

We solve it by subtitution

from equation (1) d = 4r + 100

plugging in equation 2

4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h

And distance is :

d = 4*r + 100 ⇒ d = 4 * ( 225) + 100

d = 900 + 100

d = 1000 miles

6 0

3 years ago

during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak

STatiana [176]

<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

$f(t)=-16t^{2}+64t+4$

Where,

$a=-16\\b=64\\c=4$

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

$f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0$

Using the quadratic equation:

$\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615$

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

$f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0$

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0

3 years ago