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3 years ago

8

Good night everyone be back on tomorrow sometime. Giving my mom my phone back so please dont ask me for any help in till tomorro

w don't want anyone blowing up my phone why she and my dad are sleeping.

2 answers:

KiRa [710]3 years ago

4 0

Ok I’m just answering random questions just to get points

Lana71 [14]3 years ago

3 0

Answer:

Step-by-step explanation:

XD um okay. Thanks !

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The art teacher is going to have students

nexus9112 [7]

Answer:

8.5 feet

Step-by-step explanation:

632.5-12= 620.5

620.5/73=8.5

8 0

3 years ago

Find the solution of the separable equations a) the general solution: displaystyle dy/dt = t/[y^2] b) the unique solution to: dy

Xelga [282]

Answer:

(a) The general solution of given differential equation is $\frac{y^3}{3}=\frac{t^2}{2}+C$ .

(b) The unique solution is $\frac{y^2}{2}=t-\frac{5}{2}$ .

Step-by-step explanation:

(a)

The given differential equation is

$\frac{dy}{dt}=\frac{t}{y^2}$

Use variable separable method, to solve the above differential equation.

Separate the variables.

$y^2dy=tdt$

Integrate both sides.

$\int y^2dy=\int tdt$

$\frac{y^3}{3}=\frac{t^2}{2}+C$

The general solution of given differential equation is $\frac{y^3}{3}=\frac{t^2}{2}+C$ .

(b)

The given differential equation is

$\frac{dy}{dt}=\frac{1}{y}$

Use variable separable method, to solve the above differential equation.

Separate the variables.

$ydy=1dt$

Integrate both sides.

$\int ydy=\int 1dt$

$\frac{y^2}{2}=t+C$ ... (1)

It is given that y=1 at t=3. Substitute y=1 and t=3 in the above equation.

$\frac{(1)^2}{2}=(3)+C$

$\frac{1}{2}-3=C$

$-\frac{5}{2}=C$

Substitute $C=-\frac{5}{2}$ in equation (1).

$\frac{y^2}{2}=t-\frac{5}{2}$

Therefore the unique solution is $\frac{y^2}{2}=t-\frac{5}{2}$ .

6 0

4 years ago

What is the area?<br> write your answer as a fraction or as a whole or mixed number

Soloha48 [4]

$\underline \mathcal \pink{ GIVEN}$

Base = 2 9/10 km
Height = 4 6/7 km

$\underline \mathcal \purple{ TO \: FIND}$

Area of the triangle

$\underline \mathcal \blue{CALCULATION}$

$\qquad \tt \leadsto \: area = \frac{1}{2} \times base \times height$

$\qquad \bf \nrightarrow \: area = \frac{1}{ \cancel2} \times \cancel2 \frac{9}{10} \times 4 \frac{6}{7}$

$\qquad \bf \nrightarrow \: area = \frac{9}{ \cancel{10}} \times \cancel4 \frac{6}{7}$

$\qquad \bf \nrightarrow \: area = \frac{9}{ 5} \times 2 \frac{6}{7}$

$\qquad \bf \nrightarrow \: area = \frac{108}{ 35} \approx3.08 \: {km}^{2}$

<em>Thus, The area of the triangle is 3.08 kilometers...~</em>

7 0

2 years ago

A triangular prism has a base that is 15 cm2. Its height is 6 cm. What is its

Effectus [21]

We know any prism has the below formula if volume

Area of base×Height

Here

Area of base=15cm^2
Height=6cm

$\\ \rm\hookrightarrow V=15(6)=90cm^2$

6 0

2 years ago

Both circle A and circle B have a central angle measuring 135°. The ratio of the radius of circle A to the radius of circle B is

Darina [25.2K]

7/8π

The circles have the same central angle measures; therefore, the ratio of the intercepted arcs is the same as the ratio of the radii.

4/7 = 1/2π over x

x = 7/8π

3 0

4 years ago

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