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4 years ago

HELP NEEEDED ASAP PLEASE!!!

Mathematics

1 answer:

Zielflug [23.3K]4 years ago

4 0

Answer:

im pretty sure the answers are

A) 6

b) 10

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2. Use the relationship you established in part 1 to find the m your work. (1 point)

S_A_V [24]

When faced with an unknown variable in a maths problem, it is advised to find the subject formula and then use it to solve the equation to find the answer.

<h3>What is an Unknown Variable?</h3>

This refers to the type of variable in a given equation that has to be solved for because its properties or value is not known.

Hence, we can see that when faced with an unknown variable in a given math problem, it is better to find the subject formula, then input the value of this into an equation, to find the value of the variable.

Read more about unknown variables here:

brainly.com/question/2133551

#SPJ1

8 0

2 years ago

Solve the inequality − x 2 <4 -x2<4

vagabundo [1.1K]

1 and 2 I hope this help you :)

3 0

3 years ago

Which of the following is not a property of a rectangle

In-s [12.5K]

Answer:

I would like to say A because Diagonals of a rectangle Bisect each other at a right angle.

This seems likely

Please Mark as Brainliest

Hope this Helps

5 0

3 years ago

A pan is heated to 393°F, then removed from the heat and allowed to cool in a kitchen where the room temperature is a constant 6

deff fn [24]

Answer:

The approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

Step-by-step explanation:

The formula for D, the difference in temperature between the pan and the room after t minutes is:

$D = 324\cdot e^{-0.05t}$

Compute the approximate difference in temperature between the pan and the room after 9 minutes as follows:

$D = 324\cdot e^{-0.05t}$

$=324\times e^{-0.05\times 9}\\\\=206.59$

Then the approximate temperature of the pan after it has been away from the heat for 9 minutes is:

D = P - R

206.59 = P - 69

P = 206.59 + 69

P = 275.59°F

Thus, the approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

6 0

3 years ago

I need help with no.7

ziro4ka [17]

Answer:

(a) 315°

(b) 3°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

The bearing of P from R is 180° different from the bearing of R from P it will be ...

135° +180° = 315° . . . . bearing of P from R

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

315° +48° = 363°, or 3° . . . . bearing of Q from R

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

135° -77° = 58°

As above, the reverse bearing from Q to P is ...

58° +180° = 238° . . . . bearing of P from Q

8 0

3 years ago