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vova2212 [387]
3 years ago
11

Whats 13/6 divided by 8 evaluated

Mathematics
2 answers:
madreJ [45]3 years ago
8 0

Answer:

0.27083333333 or 13/48

Step-by-step explanation:

AleksAgata [21]3 years ago
3 0

Answer:

13/48

Step-by-step explanation:

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Expand and combine like terms. (7m6 + 6)(7m6 – 6)
Darina [25.2K]
5+620=728-72=*8%fc per second
4 0
4 years ago
PC-CSIL
pav-90 [236]

The equality used is Subtraction property of equality

Option A is correct

Step-by-step explanation:

We need to identify which option best explains or justifies Step 1.

Step 1 is: -c = ax^2 + bx

The given equation is: 0 = ax^2 + bx + c

To get the equation for step 1 we need to subtract c on both sides of equation i.e using subtraction property of equality

0-c = ax^2 + bx + c-c

-c = ax^2 + bx

So, The equality used is Subtraction property of equality

Option A is correct.

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

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  • brainly.com/question/1414350

#learnwithBrainly

5 0
3 years ago
Give the following arithmetic sequence, determing the next three terms
shtirl [24]

Answer:

0.75,1,1.25

Step-by-step explanation:

increase in .25 every time.

7 0
2 years ago
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
12-22 plz help thanks
Kisachek [45]

12-22 = -10 because know I'm right and it says I have to put more words so just look at the first part

6 0
3 years ago
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