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ElenaW [278]
3 years ago
10

Translate the phrase '' Nine times the difference of a number and 3'' into an algebraic expression and then simplify ,Let x be r

epresent the real number....
Mathematics
1 answer:
Llana [10]3 years ago
8 0
Your question doesn't sound complete...the algebraic expression should equal something but this is what I ended up with 9(x+3)
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the length of a rectangle is 5 minutes longer than its with if the perimeter of the rectangle must be at least 34 units what are
stealth61 [152]

Answer:

w ≥ 6

l ≥ 11

Step-by-step explanation:

The perimeter of a rectangle is equal to P = 2l+2w where l=length and w=width. Here the length is 5 feet longer than the width or 5+w. This means the width is w. Substitute P = 34, l=5+w and w into the perimeter equation. Then solve for w.

34 ≤ 2*(5+w) + 2w

34 ≤ 10+2w+2w

34 ≤ 10+4w

24 ≤ 4w

6 ≤ w

This means the width must be at least 6 so the solution is w ≥ 6.

To find the length substitute 6 into l ≤ 5+w.

l ≤ 5 + 6

l ≤ 11

The length is l ≥ 11.

7 0
3 years ago
Find the sum. 2x^2 +26x+ 156=0
Mila [183]

Answer:

-13

Step-by-step explanation:

2x²+26x+156=0

x²+13x+78=0

x²+13x=-78

x²+13x+169/4=-143/4

(x+13/2)²=-143/4

x+13/2=(i√143)/2 or x+13/2=-(i√143)/2

x=(i√143)/2-13/2 or x=-(i√143)/2-13/2

(i√143)/2-13/2+(-(i√143)/2)-13/2=(i√143-13-i√143-13)/2=-26/2=-13

5 0
3 years ago
Read 2 more answers
Please help me with this problem!!!
Lilit [14]

3  {}^{4x  - 5}  = ( \frac{1}{27} ) {}^{2x + 10}  \\ note  \: \: that =  \\ ( \frac{1}{27} ) = ( \frac{1}{3 {}^{3} } ) = 3 {}^{ - 3}  \\  \\ 3 {}^{4x - 5}  = (3 {}^{ - 3} )  {}^{2x + 10}  \\ 3 {}^{4x + 5}  = 3 {}^{ - 3(2x + 10)}  \\ equal \:  \: bases =  > equal \: exponents

4x - 5 =  - 3(2x + 10) \\ 4x - 5 =  - 6x - 30 \\ 4x  + 6x =  - 30 + 5 \\ 10x =  - 25 \\ x =   - 2.5

7 0
2 years ago
Read 2 more answers
Help me plzzzzzzzzzz and thank you!!!
wariber [46]
I am very stuck on this answer simplify 8/12
5 0
3 years ago
A mass attached to a spring is pulled toward the floor so that its height above the floor is 10 mm (millimeters). The mass is th
e-lub [12.9K]

Answer:

a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:

b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence

Step-by-step explanation:

5 0
3 years ago
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